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3 years ago

Which is not an equation of the line going through (3, 6) and (1, –2)?

2 answers:

8 0

Answer is D. y – 2 = 4(x + 1)

not an equation of the line going through (3, 6) and (1, –2)?
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BARSIC [14]3 years ago

3 0

To solve this, find your slope-intercept equation, then convert to point-slope. y=mx+b, m=(y2-y1)/(x2-x1)=(6+2)/(3-1)=4, y=4x+b, b=y-4x=6-4(3)=-6, y=4x-6. This eliminates A. Next, convert to point-slope, y-y1=m(x-x1), This gives you y-y1=4(x-x1). Using your two points, you can get y-6=4(x-3) and y+2=4(x-1) as possible equations, which eliminates B and C, meaning your answer is D.

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Rudiy27

Answer:

520

Step-by-step explanation:

must be the answer..

7 0

3 years ago

Read 2 more answers

Please help!

Ainat [17]

(x – h)^2 + (y – k)^2 = r^2

this equation is a derivative of the equation of a circle

x^2 + y^2 = r^2
This is from the origin. If we move the in x or y then the radius will change positions in x or y

with h = -3 and k = 1

we can plug in each set of numbers and solve.

we find Z to be on the circle edge!

8 0

3 years ago

(Q6) Decide if the function is an exponential function. If it is, state the initial value and the base. y= -4.8·4^x

topjm [15]

Answer:

Step-by-step explanation:

Exponential equation takes the form $y=a*b^x$ where

a is the initial value ( a ≠ 0), and
b is the base ( b ≠ 1)

The equation given in the problem can be written as $y=-4.8*4^x$ , so it is an exponential equation, where a = -4.8 and b = 4.

Thus we can say that the initial value = -4.8 and the base is 4

The correct answer is D

3 0

3 years ago

Wrong answers will be reported

PIT_PIT [208]

The solution to the equation is p = 1/3 and q = undefined

<h3>How to solve the equation?</h3>

The equation is given as:

p^2 - 2qp + 1/q = (p - 1/3)

The best way to solve the above equation is by the use of a graphing calculator i.e. graphically

However, it can be solved algebraically too (to some extent)

Recall that the equation is given as:

p^2 - 2qp + 1/q = (p - 1/3)

Split the equation

So, we have

p^2 - 2qp + 1/q = 0

p - 1/3 = 0

Solve for p in p - 1/3 = 0

p = 1/3

Substitute p = 1/3 in p^2 - 2qp + 1/q = 0

So, we have

(1/3)^2 - 2q(1/3) + 1/q = 0

This gives

1/9 - 2/3q + 1/q = 0

This gives

2/3q + 1/q = -1/9

Multiply though by q

So, we have

2/3q^2 + 1 = -1/9q

Multiply through by 9

6q^2 + 9 = -q

So, we have

6q^2 + q + 9 = 0

Using the graphing calculator, we have

q = undefined

Hence. the solution to the equation is p = 1/3 and q = undefined