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3 years ago

Please help me with this

Mathematics

2 answers:

Alex777 [14]3 years ago

8 0

1 2/4 that the answer

yulyashka [42]3 years ago

4 0

1 2/4 one and a half

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The perimeter of a geometric figure is the sum of the lengths of its sides. If the perimeter of the pentagon to the right (five

adell [148]

Answer:

Step-by-step explanation:

Our perimeter, since we have 5 sides that are all the same length, is

P = 5s, where P is perimeter and s is the length of the sides. For us,

80 = 5s, so

s = 16

7 0

3 years ago

Four married couples have reserved eight seats in a row at the theater, starting at an aisle seat. In how many ways can they arr

prisoha [69]

Answer:

1152 ways

Step-by-step explanation:

There are 4 married coupes i.e. four women and four men.

Let us treat four women as one unit together and 4 men as one unit together.

We have 2 units which can be arrangedi in 2!= 2 ways

Among 4 women they can arrnage themselves in 4! = 24 ways

Similarly 4 men can sit in 4! ways together

Hence total number of ways

they can arrange themselves if all the women sit together and all the men sit together

= No of ways 2 units arranged * no of ways men arranged * no of ways women arranged

=2*24*24

= 1152

6 0

3 years ago

A ball is projected horizontally from the top of a building. One second later, another ball is projected horizontally from the s

ehidna [41]

Answer:

t = 0 at the start of the projection

Step-by-step explanation:

To solve this we need to find the distance between the 2 positions at any given time, then solve for the least distance

Let t be the time of the 2nd ball, so t + 1 is the time of the first ball

Let g be the gravitational acceleration, v be the horizontal velocity

the y coordinates of the first and 2nd balls

$y_1 = -g(t+1)^2/2$

$y_2 = -gt^2/2$

The x coordinates of the 1st and 2nd balls:

$x_1 = v(t+1)$

$x_2 = vt$

The distance between the 2 balls is

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

$d = \sqrt{(v(t + 1) - vt)^2 + (-g(t+1)^2/2 - (-gt^2/2))^2}$

$d = \sqrt{(vt + v - vt)^2 + g/4(t^2 - (t^2 + 2t + 1))^2}$

$d = \sqrt{v^2 + (g/4)(-2t-1)^2}$

$d = \sqrt{v^2 + (g/4)(2t+1)^2}$

As both v and g are constant and cannot be changed, d is minimum when (2t + 1) is minimum, which happens only when t is minimum = 0

7 0

3 years ago

Exercise 4.16. We choose 500 numbers uniformly at random from the interval [1.5, 4.81. (a) Approximate the probability of the ev

givi [52]

Answer:

a) 0.0801

b) 0.1910

Step-by-step explanation:

a) probability of the event that numbers start with the digit 1 =P(1.5<X<2) =(2-1.5)/(4.8-1.5)=0.1515

Here mean =np =500*0.1515 =75.76

std deviation =(np(1-p))1/2 =8.02)

probability of the event that less than 65 of the numbers start with the digit 1=P(X<65)=P(Z<(64.5-75.76)/8.02)

=P(Z<-1.4041)=0.0801

b) probability of the event of the numbers start with the digit 3 =P(3<X<4) =(4-3)/(4.8-1.5)=0.3030

Here mean =np =500*0.3030 =151.52

std deviation =(np(1-p))1/2 =10.28

probability of the event that more than 160 of the numbers start with the digit 3=P(X>160)

=1-P(Z<(160.5-151.52)/10.28)=1-P(Z<0.8743)=1-0.8090 =0.1910

7 0

4 years ago

The difference of two number is 3.Their sum is 13.Find the numbers

saul85 [17]

Answer:

8,5

Step-by-step explanation:

x-y=3

x+y=13

2x=16

x=8, y=5

3 0

3 years ago

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