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VLD [36.1K]
3 years ago
13

Plz plz help me on number 9

Mathematics
2 answers:
Gnoma [55]3 years ago
7 0
The letter of the problem is j
mojhsa [17]3 years ago
4 0
The answer is letter J
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(-4/5) (15/8) (7/3) (-1)
hram777 [196]

Answer:

7/2

Step-by-step explanation:

6 0
3 years ago
Identify the type of function represented by f(x) = 4•3^x
SVEN [57.7K]

Since the variable x is at the exponent, this is an exponential function.

To decide whether an exponential function is a growing or decaying one, we have to look at the base of the exponent.

If the base is between 0 and 1, we have exponential decay

If the base is larger than 1, we have exponential growth.

In your case the base is 3, which is larger than 1, so you have exponential growth.

Thus, <u>option d</u> is your answer

7 0
2 years ago
What is 2+9 you tell me
I am Lyosha [343]

Answer:

11

Step-by-step explanation:

6 0
3 years ago
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Solve the following quadratic by<br> completing the square.<br> y = x^2 - 6x+7
kozerog [31]

Answer:

x= 3+\sqrt{2}, \quad x= 3 -\sqrt{2}

Step-by-step explanation:

<u>Given quadratic equation</u>:

y = x^2 - 6x+7

To complete the square, begin by adding and subtracting the square of half the coefficient of the term in x:

\implies y = x^2 - 6x+\left(\dfrac{-6}{2}\right)^2-\left(\dfrac{-6}{2}\right)^2+7

\implies y = x^2 - 6x+\left(-3\right)^2-\left(-3\right)^2+7

\implies y = x^2 - 6x+9-9+7

Factor the perfect square trinomial:

\implies y=(x-3)^2-9+7

\implies y=(x-3)^2-2

To solve the quadratic, set it to zero and solve for x:

\implies (x-3)^2-2=0

\implies (x-3)^2-2+2=0+2

\implies (x-3)^2=2

\implies \sqrt{(x-3)^2}=\sqrt{2}

\implies x-3= \pm\sqrt{2}

\implies x-3+3= 3\pm\sqrt{2}

\implies x= 3\pm\sqrt{2}

Therefore, the solution to the given quadratic equation is:

x= 3+\sqrt{2}, \quad x= 3 -\sqrt{2}

6 0
1 year ago
Read 2 more answers
Find the slope of the line through each pair of points (-4,-3), (7 , 1)<br>​
Wittaler [7]
The slope of the line is 4/11. to find this use, m=y2-y1/x2-x1 :)
3 0
3 years ago
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