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3 years ago

A number n increased by 4 is -19

Mathematics

2 answers:

harkovskaia [24]3 years ago

7 0

Answer:

-23

Step-by-step explanation:

-23+4= -19

MrRa [10]3 years ago

6 0

Answer:

n=23

Step-by-step explanation:

4-23=19

meme

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torisob [31]

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32.66 units

Step-by-step explanation:

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Point A=(-2,-4) and point B=(1,20)

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$\frac{dy}{dx}=12x+14$

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$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

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Using substitution method

Substitute t=12x+14

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$dx=\frac{1}{12}dt$

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We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})$

Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

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