A 5 kg ball is suspended on one cable. Calculate the tension in the cable.

Physics

1 answer:

aleksandr82 [10.1K]3 years ago

3 0

Answer:

I'm 3 percent it is b soooooo

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You walk 45 m to the north, then turn 90° to your right and walk another 45 m How far are you from where you originally started?

docker41 [41]

C^2=a^2+b^2
c^2=45^2+45^2
c^2=4050
c=63.64
c=64
The answer is D.

3 0

4 years ago

Please help thank you

Margarita [4]

Answer:

$\theta \approx 59.036^{\circ}$ , $T_{2} \approx 23.324\,N$

Explanation:

First we build the Free Body Diagram (please see first image for further details) associated with the mass, we notice that system consist of a three forces that form a right triangle (please see second image for further details): (i) The weight of the mass, (ii) two tensions.

The requested tension and angle can be found by the following trigonometrical and geometrical expressions:

$\theta = \tan^{-1} \frac{W}{T_{2}}$ (1)