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Helga [31]
3 years ago
6

What evidence do you that suggest water waves are transverse wave​

Physics
1 answer:
svp [43]3 years ago
5 0

Answer:

If you throw a pebble into a pond, ripples

spread out from where it went in. These

ripples are waves travelling through the

water. The waves move with a transverse

motion.

Explanation:

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solong [7]

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8 0
3 years ago
Sugar is made of carbon, hydrogen, and oxygen atoms.Sugar is
patriot [66]

Answer:

Matter is everything that surrounds us. It has mass and occupies a place in space. Matter can be described by measuring the value of its properties; for example: density, color, mass, volume, etc.

al ser homogenea no se puede percibir con la vista pero si se le agrega acido sulfurico la reaccion hara que el hidrogeno y el oxigeno se evaporen dejando unicamente una masa negra de carbono

No, ya que, es una mezcla homogénea, es decir,  sus elementos están muy unidos mas no combinados de manera química, es posible separarlos pero con mucha dificultad, por tanto, es imposible diferenciarlos a simple vista. Se sabe que están distribuidos de manera uniforme, su estado es conocido como solución o disolución, tal como es el caso del azúcar.

Explanation:

I hope my answer serves you and that it is to your liking please give me cornita: 3

4 0
4 years ago
A 2-kg ball is moving with a speed of 4 m/s, and a 4-kg ball is moving with a speed of 2 m/s. What can you conclude about the of
Mila [183]
<h2>Kinetic energy of mass 4 kg ball is less than kinetic energy of mass 2 kg ball</h2>

Explanation:

Kinetic energy = 0.5 x Mass x Velocity²

For ball of mass 2 kg

           Mass, m = 2 kg

           Velocity, v = 4 m/s

           Kinetic energy = 0.5 x 2 x 4² = 16 J

For ball of mass 4 kg

           Mass, m = 4 kg

           Velocity, v = 2 m/s

           Kinetic energy = 0.5 x 4 x 2² = 8 J

Kinetic energy of mass 4 kg ball is less than kinetic energy of mass 2 kg ball

4 0
3 years ago
A horizontal 810-N merry-go-round of radius 1.60 m is started from rest by a constant horizontal force of 55 N applied tangentia
Sloan [31]

Answer:

576 joules

Explanation:

From the question we are given the following:

weight = 810 N

radius (r) = 1.6 m

horizontal force (F) = 55 N

time (t) = 4 s

acceleration due to gravity (g) = 9.8 m/s^{2}

K.E = 0.5 x MI x ω^{2}

where MI is the moment of inertia and ω is the angular velocity

MI = 0.5 x m x r^2

mass = weight ÷ g = 810 ÷ 9.8 = 82.65 kg

MI = 0.5 x 82.65 x 1.6^{2}

MI = 105.8 kg.m^{2}

angular velocity (ω) = a x t

angular acceleration (a) = torque ÷ MI

where torque = F x r = 55 x 1.6 = 88 N.m

a= 88 ÷ 105.8 = 0.83 rad /s^{2}

therefore

angular velocity (ω) = a x t = 0.83 x 4 = 3.33 rad/s

K.E = 0.5 x MI x ω^{2}

K.E = 0.5 x 105.8 x 3.33^{2} = 576 joules

6 0
3 years ago
In a downhill ski race, surprisingly, little advantage is gained by getting a running start. (This is because the initial kineti
Sergio [31]

Answer:

Part a)

v_f = 25.2 m/s

t = 5.48 s

Part b)

v_f = 25.32 m/s

t = 4.96 s

Explanation:

Part a)

When ski start from rest

v_f^2 - v_i^2 = 2 a d

on this inclined plane we know that the acceleration is given as

a = g sin\theta

a = 9.81 sin28

a = 4.6 m/s^2

now for final speed

v_f^2 - v_i^2 = 2 a d

v_f^2 - 0 = 2(4.6)(69)

v_f = 25.2 m/s

now time taken by the ski to reach the bottom is given as

v_f = v_i + at

25.2 = 0 + 4.6 t

t = 5.48 s

Part b)

Now when ski start with initial speed of 2.5 m/s

then we will have

v_f^2 - v_i^2 = 2 a d

v_f^2 - 2.5^2 = 2(4.6)(69)

v_f = 25.32 m/s

now time taken by the ski to reach the bottom is given as

v_f = v_i + at

25.32 = 2.5 + 4.6 t

t = 4.96 s

3 0
3 years ago
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