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timofeeve [1]
3 years ago
11

Chrome - eAssessment - Assignment

Mathematics
1 answer:
vodomira [7]3 years ago
6 0

Answer:

rounding to the nearest tenth

Step-by-step explanation:

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For the rhombus, what are the slopes of the two diagonals? DO NOT introduce any new variables.
Jobisdone [24]

The slopes of the two diagonals of the rhombus are: A. b - f/a - e and -a + e/b - f.

<h3>What is the Slope of a Line Segment?</h3>

To find the slope, the formula used is: change in y/change in x.

If two lines are perpendicular to each other, their slope values will be negative reciprocals.

<h3>What is the Diagonals of a Rhombus?</h3>

In a rhombus, the two diagonals in the rhombus bisects each other at angle 90 degrees. This means that the two diagonals of a rhombus are perpendicular to each other. Therefore, the slope of the diagonals of any rhombus would be negative reciprocals.

The slope of the diagonals of the rhombus given would therefore be negative reciprocals to each other.

Given two endpoints of one of the diagonals as:

(a, b) = (x1, y1)

(e, f) = (x2, y2)

Slope (m) = change in y / change in x = b - f/a - e

The negative reciprocal of b - f/a - e is -a + e/b - f.

Therefore, the slopes of the two diagonals are: A. b - f/a - e and -a + e/b - f.

Learn more about the slopes of diagonals of a rhombus on:

brainly.com/question/3050890

#SPJ1

5 0
2 years ago
The price of Philip's favorite candy has been reduced by $0.15 per piece. Philip buys 14 pieces and spends $3.22.
kompoz [17]
3.22 divided by 14 is .23.   .23 plus .15 is .38 cents per candy at regular price.
6 0
3 years ago
Read 2 more answers
Which box-and-whisker plot represents the data set?<br><br> 11, 6, 19, 14, 21, 7, 13, 15, 15
Katena32 [7]
The box and whisker plot is attached.

We first order the data from least to greatest:
6, 7, 11, 13, 14, 15, 15, 19, 21

The median is the middle value, or 14.
The lower quartile is the median of the lower half (split by the median).  This is between 7 and 11: (7+11)/2 = 18/2 = 9
The upper quartile is the median of the upper half (split by the median).  This is between 15 and 19:  (15+19)/2 = 34/2 = 17
The highest value is 21.
The lowest value is 6.

We draw the middle line of the box at 14, the median.  We draw the left side of the box at the lower quartile, 9.  We draw the right side of the box at the upper quartile, 17.  From the right side of the box, we draw a whisker to the highest value, 21. From the left side of the box, we draw a whisker to the lowest value, 6.

4 0
3 years ago
Pleasee help ASAP!! No links pleaseee!!!
Ilya [14]

Given:

The vertices of the rectangle ABCD are A(0,1), B(2,4), C(6,0), D(4,-3).

To find:

The area of the rectangle.

Solution:

Distance formula:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using the distance formula, we get

AB=\sqrt{(2-0)^2+(4-1)^2}

AB=\sqrt{(2)^2+(3)^2}

AB=\sqrt{4+9}

AB=\sqrt{13}

Similarly,

BC=\sqrt{(6-2)^2+(0-4)^2}

BC=\sqrt{(4)^2+(-4)^2}

BC=\sqrt{16+16}

BC=\sqrt{32}

BC=4\sqrt{2}

Now, the length of the rectangle is AB=\sqrt{13} and the width of the rectangle is BC=4\sqrt{2}. So, the area of the rectangle is:

A=length \times width

A=\sqrt{13}\times 4\sqrt{2}

A=4\sqrt{26}

A\approx 20

Therefore, the area of the rectangle is 20 square units.

3 0
3 years ago
Z
Anton [14]

Answer:

pa brainly po hehe need talaga points

3 0
2 years ago
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