A couple plans to have two children. What is the probability that they have exactly one boy?

Mathematics

2 answers:

Licemer1 [7]2 years ago

7 0

Answer:

1/2

Step-by-step explanation:

Setler79 [48]2 years ago

7 0

Male and female having two children. The chance of having a 1 boy is 50%

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On a Saturday, a library checked out 52 books. If 24 of the books were fiction, what is the ratio of non-fiction books to fictio

mariarad [96]

6:7
Steps:
52-24=28
24:28
24÷4 : 28÷4
6 : 7

8 0

3 years ago

Find the degree of the binomial: 3x+12

tatuchka [14]

Answer:

x = 4

Step-by-step explanation:

3x + 12

x = 12/3

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Therefore the final answer is 4

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2 years ago

Read 2 more answers

If A is a 2 × 2 matrix, then A × I = and I × A =

krok68 [10]

Since the multiplication between two matrices is not commutative, then $\vec A\, \times\,\vec I \ne \vec I \,\times \,\vec A$ , regardless of the dimensions of $\vec A$ .

<h3>Is the product of two matrices commutative?</h3>

In linear algebra, we define the product of two matrices as follows:

$\vec C = \vec A \,\times \vec B$ , where $\vec A \in \mathbb{R}_{m\times p}$ , $\vec B \in \mathbb{R}_{p\times n}$ and $\vec C \in \mathbb{R}_{m \times n}$ (1)

Where each element of the matrix is equal to the following dot product:

$c_{ij} = \left[\begin{array}{cccc}a_{i1}&a_{i2}&\ldots&a_{ip}\end{array}\right]\,\bullet\,\left[\begin{array}{ccc}b_{1j}\\b_{2j}\\\vdots\\b_{pj}\end{array}\right]$ , where 1 ≤ i ≤ m and 1 ≤ j ≤ n. (2)

Because of (2), we can infer that the product of two matrices, no matter what dimensions each matrix may have, is not commutative because of the nature and characteristics of the definition itself, which implies operating on a row of the former matrix and a column of the latter matrix.

Such "arbitrariness" means that resulting value for $c_{ij}$ will be different if the order between $\vec A$ and $\vec B$ is changed and even the dimensions of $\vec C$ may be different. Therefore, the proposition is false.