Answer:
$3 max
Step-by-step explanation:
Charge= b, Customer= c, Revenue= r
r= bc, currently, r= 16*10= $160
We know that: b+1 ⇒ c-2 and the target is r ≥ 130
So, this will all be reflected as:
b=10+x ⇒ c= 16-2x
- (10+x)(16-2x) ≥ 130
- 160 -20x +16x - 2x² ≥ 130
- -2x² - 4x + 30 ≥ 0
- x² + 2x -15 ≤ 0
- (x+1)² ≤ 4²
- x+1 ≤ 4 (negative value not considered)
- x ≤ 3
As we see the max increase amount is $3, when the revenue will be:
(10+3)*(16-3*2)= 13*10= $130
I'm gonna say no. Im not 100% sure.
Answer:
25f+100c<500
Step-by-step explanation:
He wants that total calorie count to be less than 500 cals, so we use <.
25f, means for each french fries we have 25 calrs.
100c, for each chicken wings we have 100 calories.
So inequality is 25f+100c<500.
For example, he can not eat 4 french fries and 4 wings (4*25+100*4=500 is not less from 500, it is equal), but he can eat 3 fries and 4 wings (3*25+100*4=475<500).
72 you take the number of options available in the first multiplied by the number available in the second multiplied by the number in the third multiplied by the number in the fourth
