Answer: 1:10,000
Step-by-step explanation:
given data:
distance of the nearest star system = 100,000,000
distance to size ration of the sun earth system = 10,000
therefore;
100,000,000 / 10,000
= 10,000
The order of magnitude of the distance to size ratio of the Sun- Nearest Star system is about 1:10,000 times that of the Sun-Earth system.
You don't need the apothem if the side length is known, the area can be expressed as:
A(n,s)=ns^2/(4tan(180/n)), n=number of sides and s=side length so
A(7,28)=(7*28^2)/(4tan(180/7))
A≈2848.987 ft^2
A≈2849 ft^2 (to the nearest tenth of a square foot)
Answer:
16cm
Step-by-step explanation:
Let the breadth = x
The length exceeds = x + 7
The breadth increased = x + 3
Because it said the length decreased by 4 so, the length would be:
x + 7 - 4 = x + 3
Original area:
We learn that:
area = length * breadth
x*(x+7) = (x+3)*(x+3)
x^2 + 7x = (x+3)^2
x^2 + 7x = x^2 + 6x + 9 (We also learn that (a+b)^2 = a^2 + 2ab + b^2
x^2 - x^2 + 7x - 6x = 9
x = 9 (so the breadth = 9)
The length = x + 7 = 9+7 = 16(cm)
Hope this help you :3
I'd say the answer to the first question is D) 0 to 4 with intervals of 0.2.
Because, you can't just have 1 to 4, as some of the numbers are less than 1. Of course you can't have 2 to 5 either. And intervals of 2 would be too messy.
For the second question:
I believe the answer is A. Because it's obvious that there IS one outlier, and it looks like there are two clusters.
So, the answers are: A) and D).
