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ankoles [38]
3 years ago
8

DOES ANYONE KNOW THIS?!?!​

Mathematics
2 answers:
Reil [10]3 years ago
7 0

Answer:

y/-3 = 1/6

y = 1/6 × 3

y = 0.5

mina [271]3 years ago
3 0

Answer:

-1/2 and -0.5

Explanation :

Hey! Ok so you will plug in all the value in the y to find out if it equals to 1/6.

y ÷ -3 = 1/6

<u>0.5 ÷ -3</u> = 1/6

-1/6 = 1/6 ---> NO

y ÷ -3 = 1/6

<u>-1</u><u>/</u><u>2</u><u> </u><u>÷</u><u> </u><u>-3</u> = 1/6

1/6 = 1/6 ---> YES

y ÷ -3 = 1/6

<u>-0.5 ÷ -3</u> = 1/6

1/6 = 1/6 ---> YES

y ÷ -3 = 1/6

<u>-18</u><u> </u><u>÷</u><u> </u><u>-3</u> = 1/6

6 = 1/6 ---> NO

Hope this helps, and stay safe, happy, and healthy, thank you :) !!

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Enter the terms and the coefficients of the expression.
Juliette [100K]

Answer/Step-by-step explanation:

A term is part of an expression, which could be a number, a number multiplied with a variable, a variable, or 2 variables multiplied together.

The terms in the given expression, - 60 + 7p - 3z, are -60, 7p, -3z.

Coefficient is the number that is multiplied by a variable.

The coefficients in - 60 + 7p - 3z, are: 7, -3.

4 0
3 years ago
Givea)Possible number of positive real rootsb)Possible number of negative real rootsc)Possible rational roolsd)Find the roots
CaHeK987 [17]

The function is given to be:

x^3-2x^2-3x+6

QUESTION A

We can use Descartes' Rule of Signs to check the positive real roots of a polynomial.

The rule states that if the terms of a single-variable polynomial with real coefficients are ordered by descending variable exponent, then the number of positive roots of the polynomial is either equal to the number of sign differences between consecutive nonzero coefficients, or is less than it by an even number.

If we have:

f(x)=x^3-2x^2-3x+6

The coefficients are: +1, -2, -3, +6.

We can see that there are only 2 sign changes; from the first to the second term, and from the third to the fourth term.

Therefore, there are 2 or 0 positive real roots.

QUESTION B

To find the number of negative real roots, evaluate f(-x) and check for sign changes:

\begin{gathered} f(-x)=(-x)^3-2(-x)^2-3(-x)+6 \\ f(-x)=-x-2x^2+3x+6 \end{gathered}

The coefficients are: -1, -2, +3, +6.

We can see that there is only one sign change; from the second term to the third term.

Therefore, there is 1 negative real root.

QUESTION C

To check the possible rational roots, we can use the Rational Root Theorem since all the coefficients are integers.

The Rational Root Theorem states that if the polynomial:

P(x)=a_nx^n+a_{n-1}x^{n-1}+\cdots+a_2x^2+a_1x+a_0

has any rational roots, they must be in the form:

\Rightarrow\pm\mleft\lbrace\frac{factors\text{ of }a_0}{factors\text{ of }a_n}\mright\rbrace

From the polynomial, the trailing coefficient is 6:

a_o=6

Factors of 6:

\Rightarrow\pm1,\pm2,\pm3,\pm6

The leading coefficient is 1:

a_n=1

Factors of 1:

\Rightarrow\pm1_{}

Write in the form

\Rightarrow\mleft\lbrace\frac{a_o}{a_n}\mright\rbrace

Therefore,

\Rightarrow\pm(\frac{1}{1}),\pm(\frac{2}{1}),\pm(\frac{3}{1}),\pm(\frac{6}{1})

Therefore, the possible rational roots are:

\Rightarrow\pm1,\pm2,\pm3,\pm6

QUESTION D

We can use a graph to check the roots of the polynomial. The graph is shown below:

The roots of the polynomial refer to the points when the graph intersects the x-axis.

Therefore, the roots of the polynomial are:

x=-1.732,x=1.732,x=2

7 0
2 years ago
Which ordered pair is a solution to the system?
andreev551 [17]
The answer is C.(-2,3)<span />
7 0
3 years ago
First person to answer correctly please will get voted most brainiest! PLEASE
Kobotan [32]
There’s no question!!
8 0
3 years ago
PLS FIND THE VALUE OF Y AND X THANKSSSS &lt;3
kaheart [24]

Answer:

x = 1.5

y = 8

3/4 = 1.2/2

3/4 = 6/8

7 0
3 years ago
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