3 to the power of 4:

=34
x
n
=
3
4

=3⋅3⋅3⋅3
=
3
⋅
3
⋅
3
⋅
3

=81
=
81

For example, 3 to the power of -4:

=3−4
x
n
=
3
−
4

=134
=
1
3
4

=13⋅3⋅3⋅3
=
1
3
⋅
3
⋅
3
⋅
3

=181
=
1
81

=0.012346

7 0

3 years ago

What is the factored form of the expression. (2n^2 + 5n + 3) (4n - 5)

7nadin3 [17]

So firstly, <u>the factor (4n - 5) cannot be further factored, so we will be focusing on 2n² + 5n + 3.</u>

So for this, we will be factoring by grouping. Firstly, what two terms have a product of 6n² and a sum of 5n? That would be 2n and 3n. Replace 5n with 2n + 3n:

$(2n^2 + 2n + 3n + 3)(4n - 5)$

Next, factor 2n² + 2n and 3n + 3 separately. Make sure that they have the same quantity on the inside of the parentheses:

$(2n(n+1)+3(n+1))(4n-5)$

Now we can rewrite this expression as<u> $(2n+3)(n+1)(4n-5)$ , which is your final answer.</u>

7 0

3 years ago