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The table and graph show that each banana at a market costs $0.27. Cost of Bananas Bananas (x) Cost in dollars (y) 1 0.27 2 0.54

Scrat [10]

Answer:

It Is D

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

10pts dont answer bogus or reported

ELEN [110]

Answer:

6 hours and 45 minutes

Step-by-step explanation:

162÷24=6.75

6.75=6 hours and 45 min

4 0

3 years ago

g A visit to a hospital emergency room for something as simple as a sore throat could have a mean cost of $328. Assume that this

Rasek [7]

Answer:

The cut-off dollar amount is $328.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean cost of $328, standard deviation of $82.

This means that $\mu = 328, \sigma = 82$

If you want to be in the bottom 50%, what will be the cut-off dollar amount?

The 50th percentile, which is X when Z has a pvalue of 0.5. So X when Z = 0.

$Z = \frac{X - \mu}{\sigma}$

$0 = \frac{X - 328}{82}$

$X - 328 = 0*82$

$X = 328$

The cut-off dollar amount is $328.

7 0

3 years ago

A manufacturer of chocolate candies uses machines to package candies as they move along a filling line. Although the packages ar

Elenna [48]

Answer:

We conclude that the mean amount packaged is equal to 8.17 ounces.

Step-by-step explanation:

We are given that in a particular sample of 50 packages, the mean amount dispensed is 8.171 ounces, with a sample standard deviation of 0.052 ounces.

Let $\mu$ = population mean amount packaged.

So, Null Hypothesis, $H_0$ : $\mu$ = 8.17 ounces {means that the mean amount packaged is equal to 8.17 ounces}

Alternate Hypothesis, $H_A$ : $\mu\neq$ 8.17 ounces {means that the mean amount packaged is different from 8.17 ounces}

The test statistics that will be used here is One-sample t-test statistics because we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean amount dispensed = 8.171 ounces

s = sample standard deviation = 0.052 ounces

n = sample of packages = 50

So, the test statistics = $\frac{8.171-8.17}{\frac{0.052}{\sqrt{50} } }$ ~ $t_4_9$

= 0.1359

The value of t-test statistics is 0.1359.

Also, the P-value of test-statistics is given by;

the meaning of the p-value is that the p-value is the probability of obtaining a sample mean that is equal to or more extreme than 0.001 ounces away from8.17 if the null hypothesis is true.

P-value = P( $t_4_9$ > 0.136) = More than 40% {from the t-table}

Since the P-value of our test statistics is more than the level of significance of 0.01, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the mean amount packaged is equal to 8.17 ounces.

6 0

3 years ago

1- Caleb's family room has the dimensions shown. He needs to find the area of the room so that he knows how much carpet to buy.

Rina8888 [55]

Answer: $20\frac{11}{32}\ sq\ yd$