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Aleks04 [339]
2 years ago
14

By what percent change if the numerator is decreased by 10% and the denominator is decreased by 70%

Mathematics
1 answer:
hjlf2 years ago
6 0

Answer:

It increases x3.

Step-by-step explanation:

Let's say the fraction to begin with was 100/100. Ignore the fact that it isn't fully reduced and it is an improper fraction.

10% of 100 is 10, so the numerator is now 90 (decrease=get smaller; 100-10=90).

70% of 100 is 70, so the denominator is now 30 (decrease=get smaller; 100-70=30).

Our fraction is now 90/30 which, when fully reduced, equals 3.00. Since 100/100 equals 1.00, it has increased by 2.00 (3x bigger).

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<span>Width = 6 Length = 30 We know the perimeter of a rectangle is simply twice the sum of it's length and width. So we have the expression: 72 = 2*(L + W) And since we also know for this rectangle that it's length is 6 more than 4 times it's width, we have this equation as well: L = 6 + 4*W So let's determine what the dimensions are. Since we have a nice equation that expresses length in terms of width, let's substitute that equation into the equation we have for the perimeter and solve. So: 72 = 2*(L + W) 72 = 2*(6 + 4*W + W) 72 = 2*(6 + 5*W) 72 = 12 + 10*W 60 = 10*W 6 = W So we now know that the width is 6. And since we have an expression telling us the length when given the width, we can easily determine the length. So: L = 6 + 4*W L = 6 + 4*6 L = 6 + 24 L = 30 And now we know the length as well.</span>
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