we are given
now, we can compare it with
we can find b
we get
now, we are given
How would the graph change if the b value in the equation is decreased but remains greater than 1
Let's take
b=1.8
b=1.6
b=1.4
b=1.2
now, we can draw graph
now, we will verify each options
option-A:
we know that all y-value will begin at y=0
because horizontal asymptote is y=0
so, this is FALSE
option-B:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is FALSE
option-C:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is TRUE
option-D:
we know that curves are increasing
so, the value of y will keep increasing as x increases
so, this is TRUE
option-E:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is FALSE
49 is a square given by 7x7 as is clear in your equation, 4 is a square given by 4x4 the operator given is - ( minus) you have two squares, and a difference sign a^2 - b^2 = (a-b)(a+b) 7^2 -2^2 = (7-2)(7+2) = (5)(9) = 45 it is the diffeernce of two squares
Since 9 goes into 18 and 45, and both of the integers has a y2, the GCF is 9y2
The answer is 3/9 or 1/3 chance of selecting a pair of white socks
B
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