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nasty-shy [4]
2 years ago
13

The parallelograms below are similar.

Mathematics
2 answers:
artcher [175]2 years ago
4 0

Answer:

4

30 deg

Step-by-step explanation:

AD/EH = 6/1.5 = 4

Each side in ABCD is 4 times the length of the corresponding side in EFGH.

Since EF = 1, then AB = 4 * 1 = 4

Answer: AB = 4

Angle A and angle E are corresponding angles, so they are congruent.

m<E = m<A = 30 deg

Answer: 30 deg

OLEGan [10]2 years ago
3 0

Answer:

Side AB= 4

Angle E= 30°

Step-by-step explanation:

6÷1.5=4

Scale factor is 4

1×4= 4

angle A = angle E

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25x^2+1=5 quadratic
Olenka [21]
25x² + 1 = 5

25x² + 1 - 5 = 0

25x²  - 4 = 0          By difference of two squares

(5x)² - (2)² = 0

(5x - 2)(5x + 2) = 0

5x - 2 = 0    or          5x + 2 = 0

5x = 0 + 2                5x = 0 - 2

5x = 2                      5x = -2 

x = 2/5                      x = -2/5

x = 0.4                      x = -0.4 
 

x = + 0.4  or -0.4
3 0
3 years ago
Find dy/dx by implicit differentiation.
kow [346]

dy/dx by implicit differentiation is cos(πx)/sin(πy)

<h3>How to find dy/dx by implicit differentiation?</h3>

Since we have the equation

(sin(πx) + cos(πy)⁸ = 17, to find dy/dx, we differentiate implicitly.

So, [(sin(πx) + cos(πy)⁸ = 17]

d[(sin(πx) + cos(πy)⁸]/dx = d17/dx

d[(sin(πx) + cos(πy)⁸]/dx = 0

Let sin(πx) + cos(πy) = u

So, du⁸/dx = 0

du⁸/du × du/dx = 0

Since,

  • du⁸/du = 8u⁷ and
  • du/dx = d[sin(πx) + cos(πy)]/dx

= dsin(πx)/dx + dcos(πy)/dx

= dsin(πx)/dx + (dcos(πy)/dy × dy/dx)

= πcos(πx) - πsin(πy) × dy/dx

So, du⁸/dx = 0

du⁸/du × du/dx = 0

8u⁷ × [ πcos(πx) - πsin(πy) × dy/dx] = 0

8[(sin(πx) + cos(πy)]⁷ ×  (πcos(πx) - πsin(πy) × dy/dx) = 0

Since 8[(sin(πx) + cos(πy)]⁷ ≠ 0

(πcos(πx) - πsin(πy) × dy/dx) = 0

πcos(πx) = πsin(πy) × dy/dx

dy/dx = πcos(πx)/πsin(πy)

dy/dx = cos(πx)/sin(πy)

So, dy/dx by implicit differentiation is cos(πx)/sin(πy)

Learn more about implicit differentiation here:

brainly.com/question/25081524

#SPJ1

6 0
2 years ago
Can someone please explain how to get the answer I've watched multiple videos on implicit derivatives and I still cant figure it
Arisa [49]

We're given the implicit equation

x² + 2x + y² - 4y = 12

where "implicit" means that one of the variables is considered a function of the other. In this case, the variable y = y(x) depends on the value of the variable x - in other words, the possible values of y are implied by the value of x. We then say that this equation defines y as an implicit function of x.

We're also given the implicit derivative,

dy/dx = (-2x - 2)/(2y - 4)

which tells us the rate of change y as a function of both x and y. The value of dy/dx corresponds to the slope of the tangent line to the curve defined by the implicit equation above at some point (x, y).

The tangent line is horizontal when its slope is zero. This happens when

(-2x - 2)/(2y - 4) = 0

If y ≠ 2, then we can eliminate the denominator and we're left with

-2x - 2 = 0

Solve for x :

-2x = 2

x = -1

This tells us that the points on the curve with x-coordinate -1 have a tangent line to the curve that is horizontal.

The tangent line is vertical when its slope is undefined/infinite, or equivalently when the denominator of dy/dx is zero:

2y - 4 = 0

Solve for y :

2y = 4

y = 2

So any point on the curve with y-coordinate 2 will have a tangent line there that is vertical.

By completing the square in the implicit equation, we can easily identify where these points are located.

x² + 2x + y² - 4y = 12

x² + 2x + 1 + y² - 4y + 4 = 17

(x + 1)² + (y - 2)² = 17

This equation defines a circle centered at (-1, 2) with radius √17. When x = -1, we have

(y - 2)² = 17   ⇒   y = 2 ± √17

and when y = 2, we have

(x + 1)² = 17   ⇒   x = -1 ± √17

See the attached plot to see the circle and the tangents at these points.

7 0
2 years ago
GUYS PLEASE HELPP PLSPLSOLSOAKGDJXG​
ladessa [460]

Answer:

Let S = starting point

Let ST = length of tunnel

SR = 1414 m

RT = 2236 m

Set up:

ST^2 + SR^2 = RT^2

ST^2 + (1414)^2 = (2236)

Solve for RT to find your answer.

Step-by-step explanation:

5 0
2 years ago
I've literally asked this question 5 times lol. Can someone please help me?
Tju [1.3M]
I think i know the answer to that question. just wait for a sec.
6 0
3 years ago
Read 2 more answers
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