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Maksim231197 [3]
3 years ago
13

The height of a firework shot upward from the ground with the initial velocity of 10meters per second is represented by the func

tion h(t) = - 16t2 + 4t How long did it take the firework to reach the ground
Mathematics
1 answer:
Nikolay [14]3 years ago
5 0

Answer:

0.375 seconds

Step-by-step explanation:

In simple terms, to find the time it took to reach the ground, we need to find t from the equation.

If we differentiate h with respect to t we will get the velocity with which the fireworks is moving at.

h(t) = - 16t^2 + 4t.\\dh/dt =-32t +4

We can now equate this to its velocity and solve for t

10 = -32t +4

t = 0.1875 <em>( time cannot be negative in value, so we ignore the negative sign)</em>

<em />

Therefore, the time it took the fireworks to reach the ground is = 2 x 0.1875= 0.375 seconds.

<em>(We need to account for the fact that the fireworks went up and came down)</em>

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