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Papessa [141]
3 years ago
6

What is the percent increase when 7,200 increases by 1,800?

Mathematics
1 answer:
marusya05 [52]3 years ago
7 0
The answer is 25 percent
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David conducted a study of how many college students consume coffee everyday. What type of study is this and why?
Hitman42 [59]

Answer: David conducted (an observational study) because (it studies human behavior) and (the sample is not manuipulated).

Step-by-step explanation:

hope this helps! (:

7 0
3 years ago
A department store is having sale 20%off all for all kitchen appliances what is the discount for 250$microwave
Mrrafil [7]

Answer:

200

Step-by-step explanation:

250 times 20% (.20) = 50

Subtract 50 by 250

250 - 50 = $200

8 0
3 years ago
Read 2 more answers
Kirk’s average driving speed is 5 kilometers per hour faster than Thor’s. In the same length of time it takes Kirk to drive 525
Alenkinab [10]
Let K and T be the speeds of Kirk and Thor respectively.

Note the standard definition that d=vt, distance equals velocity times time.

t=d/v

For Kirk, t=525/(T+5)

For Thor, t=490/T

Since we are told that they have traveled the same amount of time we can say t=t which leaves us:

525/(T+5)=490/T  multiply both sides by T

525T/(T+5)=490  multiply both sides by T+5

525T=490T+2450  subtract 490T from both sides

35T=2450  divide both sides by 35

T=70

So Thor's average speed is 70kph, since K=T+5

K=75kph

So Kirk's average speed is 75kph
5 0
3 years ago
Please help me solve the math question 3ab-9ab+7ab thanks
frutty [35]

Answer:

okay your welcome

Step-by-step explanation:

please give me branliest answer

8 0
3 years ago
Read 2 more answers
How Do I Solve Question 8 ?
Virty [35]
8)

\bf \left. \qquad  \right.\textit{internal division of a line segment}
\\\\\\
A(x,y)\qquad C(12,5)\qquad
\qquad AB:BC\qquad 3:4\to \frac{3}{4}
\\\\\\
\cfrac{AB}{BC} = \cfrac{3}{4}\implies \cfrac{A}{C}=\cfrac{3}{4}\implies 4A=3C\implies 4(x,y)=3(12,5)
\\\\\\
-------------------------------\\\\
{ B=\left(\cfrac{\textit{sum of "x" values}}{r1+r2}\quad ,\quad \cfrac{\textit{sum of "y" values}}{r1+r2}\right)}\\\\
-------------------------------\\\\

\bf B=\left(\cfrac{(4\cdot x)+(3\cdot 12)}{3+4}\quad ,\quad \cfrac{(4\cdot y)+(3\cdot 5)}{3+4}\right)=\stackrel{B}{(4,1)}
\\\\\\
\left(\cfrac{4x+36}{7}~,~\cfrac{4y+15}{7}  \right)=(4,1)\implies 
\begin{cases}
\cfrac{4x+36}{7}=4\\\\
4x+36=28\\
4x=-8\\
\boxed{x=-2}\\
----------\\
\cfrac{4y+15}{7}=1\\\\
4y+15=7\\
4y=-8\\
\boxed{y=-2}
\end{cases}
6 0
3 years ago
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