HELP ME PLEASE!!!

Question 4 of 30

Gemiola [76]

Answer:

1/36

Step-by-step explanation:

prob of each dice is 1/6

=1/6 * 1/6

6 0

2 years ago

40 and 400 <br>The value of 4 in ___ is______ times the value of 4 in _____

Nat2105 [25]

The value of 4 in the 400 is ten times the value of 4 in the 40's place

7 0

3 years ago

Read 2 more answers

A dairy farm uses the somatic cell count (SCC) report on the milk it provides to a processor as one way to monitor the health of

Eva8 [605]

Answer:

$t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37$

$p_v =P(t_{4}>2.37)=0.038$

If we compare the p value and a significance level assumed $\alpha=0.1$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.

Step-by-step explanation:

Data given and notation

$\bar X=250000$ represent the sample mean

$s=37500$ represent the standard deviation for the sample

$n=5$ sample size

$\mu_o =210250$ represent the value that we want to test

$\alpha=0.1$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the mean is higher than 210250, the system of hypothesis would be:

Null hypothesis: $\mu \leq 210250$

Alternative hypothesis: $\mu > 210250$

Compute the test statistic

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37$

Now we need to find the degrees of freedom for the t distirbution given by:

$df=n-1=5-1=4$

Conclusion

Since is a one right tailed test the p value would be:

$p_v =P(t_{4}>2.37)=0.038$

If we compare the p value and a significance level assumed $\alpha=0.1$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.

6 0

3 years ago

Clare paid full price for an item. Han bought the same item for 80% of the full price. Clare said, I cants believe I paid 125% o

Anettt [7]

Answer:

The statement is True!

Step-by-step explanation:

Clare paid full price for an item.

Let Price of the item = x

Han bought the same item for 80% of the full price.

Han bought it for 0.8x

Clare said, I cants believe I paid 125% of what you paid, Han!

The above statement is True if;

125% of 0.8x = x

1.25 * 0.8x = x

x =x

The statement is True!

3 0

3 years ago

Your turn on Elastic Audio for a track, and set the algorithm to Polyphonic. If you wish to adjust the tempo of Pro Tools, and h

olganol [36]

Answer:

Tick Timebase

Step-by-step explanation:

3 0

3 years ago