Is a right triangle a isosceles triangle. Why or why not? And please NO LINKS.

Mathematics

2 answers:

Oduvanchick [21]3 years ago

6 0

Answer:

An isosceles triangle is symmetrical and a right triangle has a 90 degree angle and not symmetrical so they are not the same.

Step-by-step explanation:

horsena [70]3 years ago

4 0

Explanation:

No, an isosceles triangle is not ALWAYS a right triangle. An Isosceles Triangle can be a right triangle, it is a 45–45–90 degree triangle. No, an isoceles triangle is a triangle that has 2 equal sides and angles, and the only condition for a right angled triangle is for it to have a right angle.

Answer:

No

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3 years ago

Simplify completely: 8x+4/x^3+23÷4x^2-10x-6/9-x^2

Helen [10]

Answer:

The simplified form is: $-x^2-2x+\frac{4}{x^3}+\frac{23}{4x^2}-\frac{2}{3}$

Step-by-step explanation:

To simplify the expression given we, need to open the brackets, and if there is power term. Then we need to group all the like terms and then arrange in the descending order of powers of the given expression.

Now the expression that is given to us is:

$8x+\frac{4}{x^3}+\frac{23}{4x^2}-10x-\frac{6}{9}-x^2$

Here we will simplify it by grouping the like terms, as follows:

$8x+\frac{4}{x^3}+\frac{23}{4x^2}-10x-\frac{6}{9}-x^2\\=-x^2+8x-10x+\frac{4}{x^3}+\frac{23}{4x^2}-\frac{6}{9}=-x^2-2x+\frac{4}{x^3}+\frac{23}{4x^2}-\frac{2}{3}$