Draw a triangle that has 7cm and 5 cm sides and a non-included angle of 80 degrees

Y varies directly with x, and y = 5 when x = 4. What is the value of x when y = 8?

Tomtit [17]

As y varies directly with x, there is a proportionality constant. As x increases by that certain constant, y also increases. We equate:
y = kx
where k = proportionality constant.
Given the condition, y = 5 when x = 4, then we solve for k:
5 = k(4)
k = 5/4 or 1.25
When y = 8, then
8 = (5/4)(x)
x = 8/(5/4) = (8)(4/5) = 32/5 or 6.4 (ANSWER)

7 0

3 years ago

How to estimate 96 Times 34 what is the answer

Marrrta [24]

When it says to estimate, I always think of doing it by hand to show work. So set it up like this:

96

x 34

So follow it out multiplying across 4*6 and 4*9 carrying over as needed to get it to look like this:

96

x 34

384

Do the same for the 3 to get this:

96

x 34

384

2880

Add 384+2880=3264

Your final answer is 3,264

6 0

3 years ago

Can someone help please and thank you.

natita [175]

5)

Equilateral triangle, all sides are equal

So 2x + 5 = 11

2x = 6

x = 3

Answer is the first one

3; Equilateral theorem

6)

Isosceles triangle has at least two congruent sides.

So 6x = 24

x = 4

Answer x = 4

Converse of the Base Angle Theorem

7)

5x + 7 = 52

5x = 45

x = 9

Answer

x = 9

Base angle theorem

8)

5y - 14 = 3y

2y = 14

y = 7

Answer

7; Equiangular theorem

4 0

3 years ago

A ball is projected in to the air. Its height at time t is given by the equation

Ksju [112]

The equation gives the height of the ball. That is, h is the height of the ball. t is the time. Since we are looking for the time at which the height is 8 (h=8), we need to set the equation equal to 8 and solve for t. We do this as follows:

$h=-16 t^{2} +60t+1$
$8=-16 t^{2} +60t+1$
$16 t^{2} -60t-1+8=0$
$16 t^{2} -60t+7=0$

This is a quadratic equation and as it is set equal to 0 we can solve it using the quadratic formula. That formula is:
$t= \frac{-bplus minus \sqrt{ b^{2}-4ac } }{2a}$
You might recall seeing this as "x=..." but since our equation is in terms of t we use "t-=..."

In order to use the formula we need to identify a, b and c.
a = the coefficient (number in front of) $t^{2}$ = 16.
b = the coefficient of t = -60
c = the constant (the number that is by itself) = 7

Substituting these into the quadratic formula gives us:
$t= \frac{-(-60)plus minus \sqrt{ (-60)^{2}-4(16)(7) } }{2(16)}$
$t= \frac{60plus minus \sqrt{3600-448 } }{32}$
$t= \frac{60plus minus \sqrt{3152 } }{32}$

As we have "plus minus" (this is usually written in symbols with a plus sign over a minus sign) we split the equation in two and obtain:
$t= \frac{60+56.1426}{32} =3.63$
and
$t= \frac{60-56.1426}{32} =.12$

So the height is 8 feet at t = 3.63 and t=.12

It should make sense that there are two times. The ball goes up, reaches it's highest height and then comes back down. As such the height will be 8 at some point on the way up and also at some point on the way down.

3 0

3 years ago

1a. Tell whether the angles are adjacent or vertical. *

Anton [14]

Answer:

it is adjacent and the answer to 1b is 146

3 0

3 years ago