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Free_Kalibri [48]
3 years ago
7

PLEASE HELP ME!!!! WILL GIVE 5 STAR, THX, AND BRAINLIEST!!

Mathematics
2 answers:
Elis [28]3 years ago
4 0
E fs ik that for a fact and maybe that’s all?
Harman [31]3 years ago
3 0

Answer:

E. \sqrt{2

Step-by-step explanation:

\frac{\sqrt{18}}{\sqrt{9}} = \frac{(\sqrt{9})(\sqrt2)}{3} =  \frac{(3)(\sqrt2)}{3} = (\frac{3}{3})(\frac{\sqrt{2}}{1}) = (1)(\frac{\sqrt{2}}{1}) = \sqrt{2}

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The first poster is not an accurate representation of the painting, but the second poster is an accurate representation because the ratio between the first and original lengths did not equal the ratio between the first and original widths but the second poster's ratios were equal.

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A credit card company is about to send out a mailing to test the market for a new credit card. From that sample, they want to es
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Answer:

n=\frac{0.005(1-0.005)}{(\frac{0.001}{1.96})^2}=19111.96  

And rounded up we have that n=19112

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.001 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.005(1-0.005)}{(\frac{0.001}{1.96})^2}=19111.96  

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whaddup killua

Step-by-step explanation:

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