Find the measure of each missing angle

A bank account earns interest at a rate of 3.5% per year ( in other words it increases in value by that percent) and starts with

LenKa [72]

Annually cumulating interest can be determined by the following formula:

$W = P(1+r)^{y}$

r represents the interest rate as a decimal, and P represents the starting amount of money.

8 0

3 years ago

Find the LCM of the following. A. 28,42,35 B. 48,72,96 C. 36, 44

Ne4ueva [31]

28/2= 14 42/2= 21 35/7= 5

14/ 2= 7 21/3= 7

28= 2^2 × 7

42= 2 × 3 × 7

35= 7 × 5

LCM= 420

48/2= 24. 72/2= 36. 96/3= 32

24/2= 12. 36/3= 12. 32/2= 16

12/3= 4. 12/3= 4. 16/2= 8

4/2= 2. 4/2= 2. 8/2= 4

4/2= 2

48= 2^4 × 3

72= 2^3 × 3^2

96= 2^5 × 3

LCM= 288

36/3= 12. 44/2= 22

12/3= 4. 22/2= 11

4/2= 2

36= 3^2 × 2^2

44= 2^2 × 11

LCM= 396

8 0

2 years ago

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I need help with this question

Norma-Jean [14]

d. every twentieth name on a roster of all students at school

8 0

3 years ago

(50 POINTS - WILL GIVE BRAINLIEST TO MOST HELPFUL ANSWER)

cricket20 [7]

Answer:

Part A:

x + y = 80

x + 20 = y

Part B:

Pam spends 30 minutes practicing math every day.

Part C:

It is not possible for Pam to have spent 60 minutes practicing dance because this means she must have practiced math for 40 minutes (60 - 20 = 40). This would total out to 100 minutes of total practice, not 80 minutes. Therefore, this is impossible.

Step-by-step explanation:

Part A:

"She spends 80 minutes every day practicing dance and math."

x + y = 80

"She dances for 20 minutes longer than she works on math."

x + 20 = y

Part B:

Solve for x:

x + 20 = y

Isolate variable x:

x = y - 20

Plug in this new value for the first equation:

y - 20 + y = 80

Combine like terms:

2y - 20 = 80

Isolate variable y:

2y = 100

y = 50

Plug in the new value of y into any equation:

x + 50 = 80

Isolate variable x:

x = 30

Part C:

x + 20 = y

x + 20 = 60

x = 40

x + y = 80

40 + 60 = 80

100 = 80

Impossible.

8 0

3 years ago

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What is the simplified form of the quantity of x plus 6, all over the quantity of x plus 4 + the quantity of x minus 3, all over

Rina8888 [55]

$\frac{x+6}{x+4} +\frac{x-3}{3}$

make denomenators the same

we have
x+4 and 3
times the fraction with x+4 in denomenator with the fraction 3/3
times the fraction with 3 in denomenator with the fraction x+4
we get
$\frac{3x+18}{3x+12} +\frac{x^2+x-12}{3x+12}$
since common denoms, can add them to get
$\frac{3x+18+x^2+x-12}{3x+12}$
$\frac{x^2+4x+6}{3x+12}$
that is simplified

7 0

3 years ago