Answer:
There are 8008 possible outcomes are there the first time he grabs 6 chocolates
Step-by-step explanation:
The order in which the chocolates are chosen is not important. So the combinations formula is used to solve this question.
Combinations formula:
is the number of different combinations of x objects from a set of n elements, given by the following formula.
How many possible outcomes are there the first time he grabs 6 chocolates?
6 chocolates from a set of 16. So
There are 8008 possible outcomes are there the first time he grabs 6 chocolates
Answer:
1 1/4 hours=60+15 minutes =75 minutes
hence, 75 divided by 5 = 15 five minutes intervals:)
Ans: 15 five minutes intervals
Answer:
Step-by-step explanation:
Given that Z the set of integers is the universal set and
A is given in set builder form.
To convert this into roster form, we can find solutions for x
When 
i.e. all integers lying between -2.236 and 2.236
The only integers satisfying this conditions are
-2,-1,0,1,2
Hence A in roster form is
A=
If x represents the width of the poster (including borders), the area of the finished poster can be written as
.. a = x*(390/(x -10) +8)
.. = 8x +390 +3900/(x -10)
Then the derivative with respect to x is
.. da/dx = 8 -3900/(x -10)^2
This is zero at the minimum area, where
.. x = √(3900/8) +10 ≈ 32.08 . . . . cm
The height is then
.. 390/(x -10) +8 = 8 +2√78 ≈ 25.66 . . . . cm
The poster with the smallest area is 32.08 cm wide by 25.66 cm tall.
_____
In these "border" problems, the smallest area will have the same overall dimension ratio that the borders have. Here, the poster is 10/8 = 1.25 times as wide as it is high.
Answer:
A. Increase by 2
Step-by-step explanation:
Given that a fitted multiple regression equation is
This is a multiple regression line with dependent variable y and independent variables x1, x2, x3 and x4
The coefficients of independent variables represent the slope.
In other words the coefficients represent the rate of change of y when xi is changed by 1 unit.
Given that x3 and x4 remain unchanged and x1 increases by 2 and x2 by 2 units
Since slope of x1 is 5, we find for one unit change in x1 we can have 5 units change in y
i.e. for 2 units change in x1, we expect 10 units change in Y
Similarly for 2 units change in x2, we expect -2(4) units change in Y
Put together we have
change in y
Since positive 2, there is an increase by 2
A. Increase by 2
