The total amount of water in the beaker is 0.8 Liters
calculation
convert 300 Ml in liters
that is 1 L = 1000 Ml
? = 300 Ml
by cross multiplication
1 L x300 Ml/ 1000 Ml = 0.3 Ml
total is therefore = 0.5 Ml + 0.3 Ml = 0.8 Liters
Answer is 334.35 g.
<em>Explanation:</em>
n = m/M
Where n is the number of moles of given substance (mol), m is the mass (g) and M is the molar mass of the substance (g/mol).
n = 3.99 mol
m = ?
M = 83.798 g/mol
By applying the formula,
3.99 mol = m / <span>83.798 g/mol
</span> m = 3.99 mol x <span>83.798 g/mol
</span> m = 334.35 g
Hopes this helps:
Answer: Law
A scientific law is a statement describing what always happens under certain conditions. Newton’s three laws of motion are examples of laws in physical science.
0.074Hz is the answer to that
Answer:
6.2g of NaBr are produced
Explanation:
The reaction of HBr with NaOH occurs as follows:
HBr + NaOH → NaBr + H2O
<em>Where 1 mole of each reactant produce 1 mole of NaBr</em>
To solve this question we need to find the moles of each reactant using their molar mass. With moles we can find limiting reactant and the moles (And mass) of NaBr produced, as follows:
<em>Moles HBr -Molar mass: 80.9119g/mol)-</em>
4.9g * (1mol/80.9119g) = 0.0606 moles HBr
<em>Moles NaOH -Molar mass: 40g/mol-</em>
3.86g * (1mol/40g) = 0.0965 moles NaOH
As the reaction is 1:1 and the moles of HBr < Moles NaOH, the limiting reactant is HBr and moles of NaBr produced are 0.0606 moles.
The mass of NaBr (Molar mass: 102.894g/mol) is:
0.0606 moles * (102.894g/mol) =
<h3>6.2g of NaBr are produced</h3>