You can form 9.20 L of NH₃ gas at 93.0 °C and 37.3 kPa or 2.56 L at STP. The balanced chemical equation is N₂ + 3H₂ → 2NH₃ Since all substances are gases, we can use litres instead of moles in our calculations. You don't specify the pressure and temperature of the NH₃, so I will calculate its volume in two ways.
Charles law gives the relationship between volume and temperature of gas.
It states that at constant pressure volume is directly proportional to temperature
Therefore
V/ T = k
Where V - volume T - temperature in kelvin and k - constant
V1/T1 = V2/T2
Parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
Substituting the values in the equation
267 L/ 480 K = V / 750 K
V = 417 L
Final volume is 417 L
You're off to a good start, now find the mass of H2O and put it under I mol,
then multiply 1 mol over the mass of H2O by 215 grams
