These are the steps, with their explanations and conclusions:
1) Draw two triangles: ΔRSP and ΔQSP.
2) Since PS is perpendicular to the segment RQ, ∠ RSP and ∠ QSP are equal to 90° (congruent).
3) Since S is the midpoint of the segment RQ, the two segments RS and SQ are congruent.
4) The segment SP is common to both ΔRSP and Δ QSP.
5) You have shown that the two triangles have two pair of equal sides and their angles included also equal, which is the postulate SAS: triangles are congruent if any pair of corresponding sides and their included angles are equal in both triangles.
Then, now you conclude that, since the two triangles are congruent, every pair of corresponding sides are congruent, and so the segments RP and PQ are congruent, which means that the distance from P to R is the same distance from P to Q, i.e. P is equidistant from points R and Q
Answer:
Su=10
Explaination:
So from s to u on the nunebr line is worth 2x-12. So what is s to u worth? Well. S to t on the number line = x-7. T to u =6. And 2 x is worth 12 more than s to u, using th e expression. X has to be at least 8 because otherwise the x-7 wouldn't work, and u might get s to u = 0 or a negative number.
Say x was 13, then 13 - 7 =6. So S to t =6. And r to u =6. So s to u =12. (6+6). Then check if the expression fits this answer of 12. 2x - 12. 2x = 26. 26-12=14, which doesn't match.
Let's try 14. 14-7=7. Then s to u = 7+6=13. The expression: 2x= 28. 28-12=16. 13 and 16 dont match. So we have got further away from what we need. Why don't we try going in the opposite direction. Rather than testing 13 and +1, let's now - 1 and try 12.
If x=12, then s to t =12-7=5. And s to u =6+5=11. The expression: 2x=24.-12=12. We are very close now with 11 and 12.
Lets test x=11!
S to t = 11-7=4. 4+6=10. So s to u =10.
2x=22. 22-12=10. So the expression works and the number line measurements.
The answer is su=10 and x=11.
Since y is less than x by 7 times
so in terms of x we write
x=7y
Answer:
The area will be 
where r is the length of the leash.
Step-by-step explanation:
The area of a circle is pi times the radius squared. One forth of that area is not available for the dog to run: its the corner of the house. so what's left is 3/4 of the area of the circle. (3/4)πr²
Since the length of the leash is not given in the question, no specific Area can be answered. Once that value is substituted for r, the actual area can be calculated.
Answer: the compliment is 19° (90-71=19). the supplement is 109° (180-71=109)
