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kenny6666 [7]
2 years ago
11

What are the solutions to the system of equations?

Mathematics
1 answer:
bogdanovich [222]2 years ago
5 0

Answer:

(0, - 3 ) and (- 1, - 5 )

Step-by-step explanation:

Given the 2 equations

y = 4x² + 6x - 3 → (1)

y = 2x - 3 → (2)

Substitute y = 4x² + 6x - 3 into (2)

4x² + 6x - 3 = 2x - 3 ( subtract 2x - 3 from both sides )

4x² + 4x = 0 ← factor out 4x from each term

4x(x + 1) = 0

Equate each factor to zero and solve for x

4x = 0 ⇒ x = 0

x + 1 = 0 ⇒ x = - 1

Substitute these values into (2) for corresponding values of y

x = 0 : y = 2(0) - 3 = 0 - 3 = - 3 ⇒ (0, - 3 )

x = - 1 : y = 2(- 1) - 3 = - 2 - 3 = - 5 ⇒ (- 1, - 5 )

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The area of a parellelogram is usually basically the same as that of a rectangle or square. So the equation for the area of this parellogram is 60/12.

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asambeis [7]

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I need help with this
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David borrowed $30,000 to start a business. Four years later he repaid $1260 in interest. What was the annual rate? Round to two
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