What are the solutions to the system of equations?

Mathematics

1 answer:

bogdanovich [222]2 years ago

5 0

Answer:

(0, - 3 ) and (- 1, - 5 )

Step-by-step explanation:

Given the 2 equations

y = 4x² + 6x - 3 → (1)

y = 2x - 3 → (2)

Substitute y = 4x² + 6x - 3 into (2)

4x² + 6x - 3 = 2x - 3 ( subtract 2x - 3 from both sides )

4x² + 4x = 0 ← factor out 4x from each term

4x(x + 1) = 0

Equate each factor to zero and solve for x

4x = 0 ⇒ x = 0

x + 1 = 0 ⇒ x = - 1

Substitute these values into (2) for corresponding values of y

x = 0 : y = 2(0) - 3 = 0 - 3 = - 3 ⇒ (0, - 3 )

x = - 1 : y = 2(- 1) - 3 = - 2 - 3 = - 5 ⇒ (- 1, - 5 )

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