Answer:
D
Explanation:
I believe it is D. your kinetic energy would be at b. A, the cart would be going at a constant rate, because there is no hill or steep slope.
Answer:
The enthalpy change during the reaction is -7020.09 kJ/mole.
Explanation:
First we have to calculate the heat gained by the calorimeter.
where,
q = heat gained = ?
c = specific heat =
= final temperature =
= initial temperature =
Now put all the given values in the above formula, we get:
The heat gained by water present in calorimeter. = q'
where,
q' = heat gained = ?
m = mass of water =
c' = specific heat of water =
= final temperature =
= initial temperature =
q ' = 12,060.38 J
Now we have to calculate the enthalpy change during the reaction.
where,
= enthalpy change = ?
Q = heat gained = -(q+q') = -(2,485.25 J + 12,060.38 J)= -14,545.63 J
Q = -14.54563 kJ
n = number of moles fructose =
Therefore, the enthalpy change during the reaction is -7020.09 kJ/mole.
Because we say humid air “feels” heavier, more dense, more oppressive. ... Technically there is no direct connection between air pressure and humidity, humidity is the amount of water vapor in the air or air parcel. Air pressure is the weight of the air in a column. The only true connection would be the temperature.
Answer:
C. 0.4.
Explanation:
<em>∵ mole fraction of acetic acid (X acetic acid) = (no. of moles acetic acid)/(total no. of moles) = (no. of moles acetic acid)/(no. of moles of acetic acid + no. of moles of water).</em>
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- no. of moles of acetic acid = 2, no. of moles of water = 3.
- Total no. of moles = no. of moles of acetic acid + no. of moles of water = 2 + 3 = 5.
<em>∴ mole fraction of acetic acid (X acetic acid) = (no. of moles acetic acid)/(total no. of moles) =</em> (2)/(5)<em> = 0.4.</em>