Answer:

Explanation:
1. Volume of sealed tube
Assume the sealed tube is a right circular cylinder in which the cap and the base are also 4.20 mm thick.
Its outside dimensions are 155 mm long × 10.0 mm diameter.
Its inside dimensions are
h = 155 mm - 2 × 4.20 mm = 146.6 mm
r = 5.0 mm - 4.20 mm = 0.8 mm
V = πr²h = π(0.8)²× 146.6 mm³ = 294.8 mm³ = 0.2948 cm³
2. Calculate the mass of NH₃
Homogeneous mixture<span>steel
</span>element<span>sodium
</span>mixture, homogeneous<span>brass
</span>
Answer:

Explanation:
Hello there!
In this case, since the titration of acids like KHP with bases like NaOH are performed in a 1:1 mole ratio, it is possible for us to know that their moles are the same at the equivalence point, and the concentration, volume and moles are related as follows:

Thus, by solving for the volume of the base as NaOH, we obtain:

Best regards!
It is option A 4s cause n=4, l=1 this is 4s orbital