Answer:

Geela would need 9 yellow parts

Explanation:

Originally, the Geela needed more yellow than red and the difference was 4 parts.

6-2=4 parts

4 parts + 5 parts of yellow = 9 yellow parts.

3 0

2 years ago

can someone please help me with this? i know it’s change of base formula i just don’t know how to work it out

ANTONII [103]

I still cant see it sorry cant help without seeing it can you spell the question?

3 0

2 years ago

In how many ways can a quality-control engineer select a sample of3 transistors for testing frm a batch of 100 transistors?

Advocard [28]

Answer:

161700 ways.

Step-by-step explanation:

The order in which the transistors are chosen is not important. This means that we use the combinations formula to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

3 transistors from a set of 100. So

$C_{100,3} = \frac{100!}{3!(100-3)!} = 161700$

So 161700 ways.

6 0

3 years ago