Nick walked 3/4 of a mile in 12 minutes.How long would it take him to walk three miles at this pace

Mathematics

2 answers:

natima [27]2 years ago

7 0

Answer:

Step-by-step explanation:

I love math, so this was fun! First, we need to know how long it would take him to walk 1 mile. We know it took 12 minutes to walk 3/4 of a mile, so we just need to figure out how long each quater is. For this problem, each quarter of a mile is 3 minutes, and so we just need to multiply that by 4. then, we know it would take him 15 mintues to walk a mile. Then, just multiply that by 3! Hope this helps, sorry I can't spell :)

Gekata [30.6K]2 years ago

4 0

Answer:

48 minutes

Step-by-step explanation:

First do 3 divided by 3/4 and that gives you 4. Then multiply 4 by 12 and you get 48.

You might be interested in

There are 32 students in Joe's class. Of the 32 students, 8 students ride their bikes to school, 5 walk to school, 4 ride to sch

vampirchik [111]

Answer:

5/32 (aka option A) should be the correct answer!

Step-by-step explanation:

ok so... its 5/32 who walks to school!

since there are 5 students who walked to school, and 32 students are in the class, 5/32 should be the correct answer!

3 0

2 years ago

Read 2 more answers

The Information Technology Department at a large university wishes to estimate the proportion of students living in the dormitor

nadya68 [22]

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16$

And rounded up we have that n=385

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by: