Hello there! How are you today?
5a^2 + 2b^3, solve when a = 4 and b = -4
To solve for this, we must replace "a" with 4, and "b" with -4.
I will set it up;
5(4^2) + 2(-4^3)
Simplify the parenthesis (PEMDAS).
5(16) + 2(-64)
Remove the parenthesis by multiplying them by the numbers to the outside of them.
5 x 16 = 80
2 x -64 = -128
We are now left with:
80 - 128
Simplify.
-48 is your final answer.
I hope this helps!
Given :
When 7 is subtracted from five times a number, the result is greater than twice the sum of the number and 4.
To Find :
All the numbers that satisfy the inequality.
Solution :
Let , the number is x .
Mathematical expression for first term is :
5x - 7
Mathematical expression for second term is :
2(x + 4)
Now , comparing both the expression by given constrain.
So, all the numbers that satisfy the inequality are greater than 5.
Hence , this is the required solution.
Div·i·dend<span>ˈdivəˌdend/</span>noun<span>1.a sum of money paid regularly (typically quarterly) by a company to its shareholders out of its profits (or reserves).<span />2.MATHEMATICSa number to be divided by another number.
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The product is 1,127.98853 ⇨ 5 digits follow after the decimal point. Hope that helps
