F = m × g
Now when, a force acts on the object at an angle and in downwards, thus formula becomes:
= N = mg + F sin(x)
Here,
- N = normal force, m = mass , g = acceleration due to gravity, F = outside force, x = the angle formed
See, as we habe to calculate the weight, which is m × g, thus we will recreate thus formula like thus:
= N = w + F sin(x) --------- [Weight = w]
Now, the solutions becomes easy from here, just put the values:
= N = w + F sin(x)
= 200 = w + 90 × sin(32)
= 200 = w + 90 × 0.55
= 200 = w + 49.5
= 200 - 49.5 = w
= 150.5 = w
I have got my answer but in approx, hope you will not mind. ^^"
position of the peg is given by the equation
now the rate of change in position is given as
given that
now we have
<em>so its speed will be 3.76 m/s in magnitude</em>
The gravitational force experienced by Earth due to the Moon is <u>equal to </u>the gravitational force experienced by the Moon due to Earth.
<u>Explanation</u>:
The force that attracts any two objects/bodies with mass towards each other is defined as gravitational force. Generally the gravitational force is attractive, as it always pulls the masses together and never pushes them apart.
The gravitational force can be calculated effectively using the following formula: F=GMmr^2
where “G” is the gravitational constant.
Though gravity has the ability to pull the masses together, it is the weakest force in the nature.
The mass of the Earth and moon varies, but still the gravitational force felt by the Earth and Moon are alike.
Answer:
W = 68 J
Explanation:
On a force vs displacement chart, work is the area under the curve.
The area under the curve can be divided into a rectangle and a triangle
W = Fd = (2 N)(12 - 0 m) + ½(13 - 2 N)(12 - 4 m) = 68 N•m = J
Answer:
This causes higher average tidal ranges. The gravitational pull of the Sun and moon on Earth combined cause high tides that will be higher and low tides that will be lower than average.
