All categories

3 years ago

Please help me solve this problem 3x+9 ?

Mathematics

1 answer:

maxonik [38]3 years ago

3 0

Assuming that the expression equals 0

3x+9=0

Subtract 9

3x= -9

-9/3= -3

x= -3

You might be interested in

How do you use a number line to solve 235+123

Novosadov [1.4K]

<span>Number line refers to a mathematical process of solving the equation with the use of lines.
=> 235 + 123
Starting from 0 you count 1 up to 235. Then starting from 235 you additionally count another 123.
Then from zero start counting the total number to the line you stopped when adding 123 to 235.

This simply equals to
=> 235 + 123
=> 358.
Pls. see attached image for illustration of number line.</span>Answer here

6 0

3 years ago

Find the value of 8/15×2/13 Although these numbers aren't quite as nice as the ones from the example, the procedure is the same,

xz_007 [3.2K]

Answer:

$\frac{16}{195}$

Step-by-step explanation:

To obtain the result of a fractions multiplication we need to multiply both numerators and the divide by the multiplication of the denomitators. In general, given a,b,c,d real numbers with b and d not zero, we have that

$\frac{a}{b}*\frac{c}{d}=\frac{a*c}{b*d}$

Substituting a,b,c and d for 8,15,2 and 13 we obtain that

$\frac{8}{15}* \frac{2}{13} =\frac{16}{195}$

3 0

3 years ago

The price of a visit to the dentist is \$50$50dollar sign, 50. If the dentist fills any cavities, an additional charge of \$100$

liubo4ka [24]

An expression for the cost will be 50+100n, where n is the number of cavities.

6 0

3 years ago

Read 2 more answers

I DONT KNOW THESE! HELP!

kkurt [141]

Answer:

20. x = 5, y = -2

21. x = 11, y = 12

22. x = 22, y = 11

23. x = 11, y = 10

Step-by-step explanation:

20. Opposite sides in the parallelogram are congruent, so

$2y+18=3x-1\\ \\6x-3=17-5y$

Solve this system of two equations:

$\left\{\begin{array}{l}2y-3x=-19\\ \\6x+5y=20\end{array}\right.$

Multiply the first equation by 2 and add two equations:

$2(2y-3x)+6x+5y=2\cdot (-19)+20\\ \\4y-6x+6x+5y=-38+20\\ \\9y=-18\\ \\y=-2$

Substitute it into the first equation:

$2\cdot (-2)-3x=-19\\ \\-3x=-19+4\\ \\-3x=-15\\ \\x=5$

21. Opposite angles in the parallelogram are congruent, so

$11x+5=10y+6$

Consecutive angles are supplementary, so

$6x-y+11x+5=180^{\circ}$

Solve this system of two equations:

$\left\{\begin{array}{l}11x-10y=1\\ \\17x-y=175\end{array}\right.$

From the second equation

$y=17x-175$

Substitute it into the first equation:

$11x-10(17x-175)=1\\ \\11x-170x+1750=1\\ \\-159x=-1749\\ \\x=11\\ \\y=17\cdot 11-175=187-175=12$

22. Opposite angles in the parallelogram are congruent, so

$2x-5=3y-12$

Consecutive angles are supplementary, so

$2x-5+7y+x=180^{\circ}$

Solve this system of two equations:

$\left\{\begin{array}{l}2x-3y=-7\\ \\3x+7y=185\end{array}\right.$

From the first equation

$x=-3.5+1.5y$

Substitute it into the second equation:

$3(-3.5+1.5y)+7y=185\\ \\-10.5+4.5y+7y=185\\ \\-105+45y+70y=1,850\\ \\115y=1,850+105\\ \\115y=1,955\\ \\y=17\\ \\x=-3.5+1.5\cdot 17=22$

23. Opposite sides in the parallelogram are congruent, so

$2x+9=4y-9\\ \\3x-5=2y+8$

Solve this system of two equations:

$\left\{\begin{array}{l}2x-4y=-18\\ \\3x-2y=13\end{array}\right.$

Multiply the second equation by 2 and subtract it from the first equation:

$2x-4y-2(3x-2y)=-18-2\cdot 13\\ \\2x-4y-6x+4y=-18-26\\ \\-4x=-44\\ \\x=11$

Substitute it into the first equation:

$2\cdot 11-4y=-18\\ \\-4y=-18-22\\ \\-4y=-40\\ \\y=10$

3 0

3 years ago

What are the ratios of sine, cosine, and tangent for angle Y? sin(Y) = StartFraction X Z Over X Y EndFraction; cos(Y) = StartFra

Sholpan [36]

Answer:

$\sin Y= \frac{XZ}{XY}$

$\cos Y= \frac{YZ}{XY}$

$\tan Y= \frac{XZ}{YZ}$

Step-by-step explanation:

Given

See attachment for triangle

Required

Find $\sin, \cos$ and $\tan$ of angle Y

For angle Y:

$Opposite = XZ$

$Adjacent = YZ$

$Hypotenuse = XY$

The $\sin$ of an angle is calculated as:

$\sin\theta = \frac{Opposite}{Hypotenuse}$

So:

$\sin Y= \frac{XZ}{XY}$

The $\cos$ of an angle is calculated as:

$\cos\theta = \frac{Adjacent}{Hypotenuse}$

So:

$\cos Y= \frac{YZ}{XY}$

The $\tan$ of an angle is calculated as:

$\tan\theta = \frac{Opposite}{Adjacent}$

So:

$\tan Y= \frac{XZ}{YZ}$

7 0

2 years ago

Read 2 more answers