Answer:
Probability ball: white - P(W)P(W);
Probability ball: even - P(E)P(E);
Probability ball: white and even - P(W&E).
Probability ball picked being white or even: P(WorE)=P(W)+P(E)-P(W&E).
(1) The probability that the ball will both be white and have an even number painted on it is 0 --> P(W&E)=0 (no white ball with even number) --> P(WorE)=P(W)+P(E)−0P(WorE)=P(W)+P(E)−0. Not sufficient
(2) The probability that the ball will be white minus the probability that the ball will have an even number painted on it is 0.2 --> P(W)−P(E)=0.2P(W)−P(E)=0.2, multiple values are possible for P(W)P(W) and P(E)P(E) (0.6 and 0.4 OR 0.4 and 0.2). Can not determine P(WorE)P(WorE).
(1)+(2) P(W&E)=0 and P(W)−P(E)=0.2P(W)−P(E)=0.2 --> P(WorE)=2P(E)+0.2P(WorE)=2P(E)+0.2 --> multiple answers are possible, for instance: if P(E)=0.4P(E)=0.4 (10 even balls) then P(WorE)=1P(WorE)=1 BUT if P(E)=0.2P(E)=0.2 (5 even balls) then P(WorE)=0.6P(WorE)=0.6. Not sufficient.
Answer: E.
Area of cone=3.14*9+3*6*3.14=27*3.14
=84.78 cm^2 if we cut into four identical pieces we get two triangle surfaces also for 1 piece and and 1/4 of the original surface area =21.195+15.588=36.783squarecm
Answer:
x = -0.5
Step-by-step explanation:
From your last step:
6.8x + 9.3 = -2.6 - 17x
We have two terms with x in them on different sides of the equation, so we want to bring the 'x terms' over to the same side.
Add 17x to both sides of the equation.
6.8x + 17x + 9.3 = -2.6
Collect like terms
23.8x + 9.3 = -2.6
Subtract 9.3 from both sides
23.8x = -2.6 - 9.3
23.8x = -11.9
Divide both sides by 23.8
x = -0.5
