Answer:
B, C, D
Step-by-step explanation:
In this problem, the range is what the output, or y, can be. The origin, or the middie of the graph, is when x=0 and y=0. From the 10s on the screen, we can gather that 5 lines = a distance of 10 on the graph. Using this information, we can say
5 lines = distance of 10
divide both sides by 5 to find the distance for each line
1 line = distance of 2
The function goes from y=0 to three lines down, for a distance of 6. The range is therefore [-6,0] as all values from -6 to 0 on the y axis are included on the graph, including 0 and -6. In this range, -6, -2, and -1 are all included.
2.5y + 3x = 27
5x - 2.5y = 5
Align the variables to make solving this easier.
2.5y + 3x = 27
-2.5y + 5x = 5
You can see that the 2.5y and -2.5y cancel each other out. Then add the 3x and 5x, and 27 + 5.
3x = 27
5x = 5
8x = 32
Divide both sides by 8.
x = 4
Now input that x into one of the equations to get y.
2.5y + 3(4) = 27
2.5y + 12 = 27
2.5y = 15
y = 6
The answer to this system of equations is x = 4, y = 6. (4, 6)
Answer:
idk bro but ily
Step-by-step explanation:
Answer:
yes that is right
Step-by-step explanation:
Answer:
x = 50
Step-by-step explanation:
Since MNP is a tangent to the circle at N, then
∠ ONP = 90° , so
∠ ONL = 90° - 55° = 35°
OL = ON ( both radii of the circle )
Thus Δ ONL is isosceles and the base angles are congruent
∠ OLN = ∠ ONL = 35°
JKLN is a cyclic quadrilateral whose opposite angles are supplementary, that is
∠KJN + ∠ KLN = 180 , substitute values
95 + 35 + x = 180
130 + x = 180 ( subtract 130 from both sides )
x = 50
