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alexandr1967 [171]
3 years ago
9

The double number line shows that 4 pounds of tomatoes cost $14. How much does it cost for 1 pound of tomatoes

Mathematics
2 answers:
Genrish500 [490]3 years ago
5 0

Answer: 3.5

Step-by-step explanation: it is 3.5 dollars because if you divide 14 by four it shows that one pound cost 3.5 dollars

Anton [14]3 years ago
4 0

Answer:

3.5

Step-by-step explanation:

You would do 14 divided by 4.

1pound =3.5

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F(x)=4x squared −7x+7, Find f(2)
Lana71 [14]

Answer: 9

Step-by-step explanation:

4x²-7x+7   f(2)=4*(2)^2-7(2)+7=16-14+7=9

7 0
2 years ago
Use the trend line to predict what the value of variable N will be when variable M equals 50.
ahrayia [7]

Answer:

N = 10

Step-by-step explanation:

Normally the coordinate system goes:

x axis (horizontal)

y axis (vertical)

Here, we have:

Horizontal axis as "M", and

Vertical axis as "N"

We want to know what N will be when M equals 50.

So, we look at the x-axis and go to M equals 50.

Then we move up until the "trend line". The intersection.

If we move directly left to vertical axis (N variable), we see that it is at the point:

N = 10

So,

When M = 50, N = 10

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3 years ago
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2 years ago
This is finding exact values of sin theta/2 and tan theta/2. I’m really confused and now don’t have a clue on how to do this, pl
Lostsunrise [7]

First,

tan(<em>θ</em>) = sin(<em>θ</em>) / cos(<em>θ</em>)

and given that 90° < <em>θ </em>< 180°, meaning <em>θ</em> lies in the second quadrant, we know that cos(<em>θ</em>) < 0. (We also then know the sign of sin(<em>θ</em>), but that won't be important.)

Dividing each part of the inequality by 2 tells us that 45° < <em>θ</em>/2 < 90°, so the half-angle falls in the first quadrant, which means both cos(<em>θ</em>/2) > 0 and sin(<em>θ</em>/2) > 0.

Now recall the half-angle identities,

cos²(<em>θ</em>/2) = (1 + cos(<em>θ</em>)) / 2

sin²(<em>θ</em>/2) = (1 - cos(<em>θ</em>)) / 2

and taking the positive square roots, we have

cos(<em>θ</em>/2) = √[(1 + cos(<em>θ</em>)) / 2]

sin(<em>θ</em>/2) = √[(1 - cos(<em>θ</em>)) / 2]

Then

tan(<em>θ</em>/2) = sin(<em>θ</em>/2) / cos(<em>θ</em>/2) = √[(1 - cos(<em>θ</em>)) / (1 + cos(<em>θ</em>))]

Notice how we don't need sin(<em>θ</em>) ?

Now, recall the Pythagorean identity:

cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1

Dividing both sides by cos²(<em>θ</em>) gives

1 + tan²(<em>θ</em>) = 1/cos²(<em>θ</em>)

We know cos(<em>θ</em>) is negative, so solve for cos²(<em>θ</em>) and take the negative square root.

cos²(<em>θ</em>) = 1/(1 + tan²(<em>θ</em>))

cos(<em>θ</em>) = - 1/√[1 + tan²(<em>θ</em>)]

Plug in tan(<em>θ</em>) = - 12/5 and solve for cos(<em>θ</em>) :

cos(<em>θ</em>) = - 1/√[1 + (-12/5)²] = - 5/13

Finally, solve for sin(<em>θ</em>/2) and tan(<em>θ</em>/2) :

sin(<em>θ</em>/2) = √[(1 - (- 5/13)) / 2] = 3/√(13)

tan(<em>θ</em>/2) = √[(1 - (- 5/13)) / (1 + (- 5/13))] = 3/2

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