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Hoochie [10]
3 years ago
7

Select the correct answer. Ruby wants to create a cube puzzle game. For that she has to create a cube. Which drafting tool do yo

u think she should use to create the cube? ОА. a French curve and a ruler OB a compass and a protractor Oc. a ruler and a protractor OD. a triangle and a T-Square O E. a ruler and a compass​
Engineering
1 answer:
Alexxx [7]3 years ago
3 0

Answer:

D. a triangle and a T-Square

Explanation:

A T-Square is the best drawing tool to create squares. You would need a squares to create cubes.

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What is the difference between an arch and a dome?
bonufazy [111]
This is an arch, its basically a half circle attach to a rectangle, you could also think of it as an upside down U. A dome is a Sphere with the inside hollowed out.

1 difference is a dome is a 3 dimensional shape while an arch is normally not. Or that a dome is the complete shape with a arch act as it’s diameter.

4 0
2 years ago
Internal service quality means that an entire organization,
svetoff [14.1K]
True

Internal service are base on customer needs.

The customers are the priority
7 0
2 years ago
How can I solve 23.5 million Nona meters to millimeters using no calculator because I have to show my work
lozanna [386]

Answer:

its so simple. u must mind some formulas.

Explanation:

mili->10^(-3)

micro->10^(-6)

nano->10^(-9)

so write the exact number and move "." to left or right depend question.

in this one:

23.5 is 23500000.0 nano with a default dot at the end

for turning to mili u must move the dot 6 steps to left so it will be: 23.5 milimeter.

6 0
3 years ago
6.39 A particular machine part is subjected in service to a maximum load of 10 kN. With the thought of providing a safety factor
Serggg [28]

Answer:

2.275 %

Explanation:

see the attached picture for detailed answer.

8 0
3 years ago
1kg of air (R 287 J/kgK) fills a weighted piston-cylinder device at 50kPa and 100°C. The device is cooled until the temperature
Reika [66]

Answer:

the work done during this cooling is −28.7 kJ

Explanation:

Given data

mass (m) = 1 kg

r = 287 J/kg-K

pressure ( p) = 50 kPa

temperature (T) = 100°C = ( 100 +273 ) = 373 K

to find out

the work done during this cooling

Solution

we know the first law of thermodynamics

pv = mRT     ....................1

here put value of p, m R and T and get volume v(a) when it initial stage in equation 1

50 v(a) = 1 × 0.287  × 373

v(a) = 107.051 / 50

v(a) = 2.1410 m³    .......................2

now we find out volume when temperature is  0°C

so put  put value of p, m R and T and get volume v(b) when temperature is cooled in equation 1

50 v(b) = 1 × 0.287  × 273

v(a) = 78.351 / 50

v(a) = 1.5670 m³    .......................3

by equation 2 and 3 we find out work done to integrate the p with respect to v i.e.

work done = \int\limits^a_b {p} \, dv

integrate it and we get

work done = p ( v(b) - v(a)  ) ................4

put the value p and v(a) and v(b) in equation 4 and we get

work done = p ( v(b) - v(a)  )

work done = 50 ( 1.5670 - 2.1410 )

work done = 50 ( 1.5670 - 2.1410 )

work done = 50 (−0.574)

work done = −28.7 kJ

here we can see work done is negative so its mean work done opposite in direction of inside air

'

7 0
3 years ago
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