Explanation:
first changing kilo ohm to ohm
860000 = 860 kΩ
and change 34 micro ampare to ampare
34 μA=3.4×10^-5
recalling the equation V=I*R
V= 3.4×10^-5×860000
v=29.24
Explanation:
thermal expansion ∝L = (δL/δT)÷L ----(1)
δL = L∝L + δT ----(2)
we have δL = 12.5x10⁻⁶
length l = 200mm
δT = 115°c - 15°c = 100°c
putting these values into equation 1, we have
δL = 200*12.5X10⁻⁶x100
= 0.25 MM
L₂ = L + δ L
= 200 + 0.25
L₂ = 200.25mm
12.5X10⁻⁶ *115-15 * 20
= 0.025
20 +0.025
D₂ = 20.025
as this rod undergoes free expansion at 115°c, the stress on this rod would be = 0
Answer:
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Explanation:
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Technical Drawings give a better understanding of what is needed and required in the project.
Explanation: