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Olegator [25]
3 years ago
7

Select the correct answer.

Engineering
1 answer:
Ulleksa [173]3 years ago
4 0
The answer is A. Immediately inform her colleague
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Which of the following refers to software designed to alter system files and utilities on a victim’s system with the intention o
Oksi-84 [34.3K]
The answer is Rootkits.
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3 years ago
What is the objective of phasing out an INDUCTION MOTOR before putting the machine into commission?
enyata [817]

The main objective of phasing out an INDUCTION MOTOR is to identify the ends of the stator coils.

<h3>What is an induction motor?</h3>

An induction motor is a device based on alternate electricity (AC) which is composed of three different stator coils.

An induction motor is a device also known as an asynchronous motor due to its irregular velocity.

In conclusion, the objective of phasing out an INDUCTION MOTOR is to identify the ends of the stator coils.

Learn more on induction motors here:

brainly.com/question/15721280

#SPJ1

8 0
2 years ago
All of the dimensions on an aircraft drawing are_________<br> to the bottom of the drawing.
Jet001 [13]
All of the dimensions on an aircraft drawing are _________ to the bottom of the drawing


Answer: parallel
7 0
2 years ago
64A geothermal pump is used to pump brine whose density is 1050 kg/m3at a rate of 0.3 m3/s from a depth of 200 m. For a pump eff
grin007 [14]

Answer:

835,175.68W

Explanation:

Calculation to determine the required power input to the pump

First step is to calculate the power needed

Using this formula

P=V*p*g*h

Where,

P represent power

V represent Volume flow rate =0.3 m³/s

p represent brine density=1050 kg/m³

g represent gravity=9.81m/s²

h represent height=200m

Let plug in the formula

P=0.3 m³/s *1050 kg/m³*9.81m/s² *200m

P=618,030 W

Now let calculate the required power input to the pump

Using this formula

Required power input=P/μ

Where,

P represent power=618,030 W

μ represent pump efficiency=74%

Let plug in the formula

Required power input=618,030W/0.74

Required power input=835,175.68W

Therefore the required power input to the pump will be 835,175.68W

5 0
3 years ago
A small lake with volume of 160,000 m^3 receives agricultural drainage waters that contain 150 mg / L total dissolved solids (TD
Stels [109]

Answer:

Explanation:

Given that : -

The desirable limit is 500 mg / l , but

allowable upto 2000 mg / l.

The take volume is V = 160.000 m3

V = 160 , 000 x 103 l

The crainage gives 150 mg / l and lake has initialy 100 mg / l

Code of tpr frpm drawn = 150 x 60, 000 x 1000

Ci = 9000 kg / gr

Cl = 100 x 160,000 x 1000

Cl = 16, 000 kg

Since allowable limit = 2000 mg / l

Cn = ( 2000 x 160, 00 x 1000 )

= 320, 000 kg

so, each year the rate increases, by 9000 kg / yr

Read level = ( 320, 000 - 16,000 )

Li = 304, 000 kg

Tr=<u>304,000</u>

      900

=33.77

5 0
3 years ago
Read 2 more answers
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