Answer: Attached below is the well written question and solution
answer:
i) Attached below
ii) similar parameter = 
Explanation:
Using ; L as characteristic length and Vo as reference velocity
i) Nondimensionalize the equations
ii) Identifying similarity parameters
the similar parameters are =
Attached below is the detailed solution
Answer:
L= 312.75 mm
Explanation:
given data
elastic modulus E = 106 GPa
cross-sectional diameter d = 3.9 mm
tensile load F = 1660 N
maximum allowable elongation ΔL = 0.41 mm
to find out
maximum length of the specimen before deformation
solution
we will apply here allowable elongation equation that is express as
ΔL = 
....................1
put here value and we get L
L = 
solve it we get
L = 0.312752 m
L= 312.75 mm
Answer:
b. Discharging; anode; cathode
Explanation:
When discharging , it means the battery is producing a flow electric current, the lithium ions are released from the anode to the cathode which generates the flow of electrons from one side to another. When charging Lithium ions are released by the cathode and received by the anode.
Answer:
The solution code is written in Python.
- def largest3(num1, num2, num3):
- largest = num1
- if(largest < num2):
- largest = num2
-
- if(largest < num3):
- largest = num3
-
- return largest
- first_num = int(input("Enter first number: "))
- second_num = int(input("Enter second number: "))
- third_num = int(input("Enter third number: "))
- largest_number = largest3(first_num, second_num, third_num)
- print("The largest number is " + str(largest_number))
Explanation:
<u>Create function largest3</u>
- Firstly, we can create a function <em>largest3 </em>which take 3 numbers (<em>num1, num2, num3</em>) as input. (Line 1).
- Please note Python uses keyword <em>def </em>to denote a function. The code from Line 2 - 10 are function body of <em>largest3</em>.
- Within the function body, create a variable,<em> largest</em>, to store the largest number. In the first beginning, just tentatively assign<em> num1 </em>to<em> largest</em>. (Line 2)
- Next, proceed to check if the current "<em>largest</em>" value smaller than the<em> num2 </em>(Line 4). If so, replace the original value of largest variable with <em>num2</em> (Line 5).
- Repeat the similar comparison procedure to<em> </em><em>num3</em> (Line 7-8)
- At the end, return the final value of "<em>largest</em>" as output
<u>Get User Input</u>
- Prompt use input for three numbers (Line 13 -15) using Python built-in <em>input</em> function.
- Please note the input parts of codes is done outside of the function <em>largest3</em>.
<u>Call function to get largest number and display</u>
- We can simply call the function<em> largest </em>by writing the function name <em>largest</em> and passing the three user input into the parenthesis as arguments. (Line 17)
- The function <em>largest </em>will operate on the three arguments and return the output to the variable <em>largest_number</em>.
- Lastly, print the output using Python built-in <em>print</em> function. (Line 18)
- Please note the output parts of codes is also done outside of the function<em> largest3</em>.
Answer: resistor
Explanation: Not quite sure. Need more research
