Oxidation number is defined as the total number of electrons that are gained or lost by the atom to form a chemical bond.
the oxidation number of the compound H₂S is 0.
the sum of the oxidation numbers of the individual elements should add up to the oxidation number of the compound.
(oxidation number of H x 2 H ions) + oxidation number of S = 0
since we know the oxidation number of H, lets name the oxidation number of S = x
(+1 * 2 )+ (x) = 0
2 + x = 0
x = -2
oxidation number of S is -2
In order to solve this type of problem, we take a look at the subscript of each element involved in the compound. These values signifies the number of particles present of that element in that compound. The calculation is as follows:
2.4 moles P2O10 ( 2 moles P / 1 moles P2O10 ) = 4.8 moles P
Answer:
1100mL
Explanation:
V of a rectangular prism = l*w*h
= 12cm*20cm*5cm
=1100cm^3
1 cm^3 = 1mL
so 1100cm^3 = 1100mL
Explanation: Si4H10+O2>SiO2+H2O
2Si4H10 + 13O2 = 8SiO2 + 10H2O
The correct answer should be "longer than".
