1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jenyasd209 [6]
3 years ago
7

In the compound h2s hydrogen has an oxidation number of 1+ and sulfur has an oxidation number of

Chemistry
2 answers:
AlladinOne [14]3 years ago
8 0

Answer:

the answer is -2

Explanation:

elena-14-01-66 [18.8K]3 years ago
3 0
Oxidation number is defined as the total number of electrons that are gained or lost by the atom to form a chemical bond. 
the oxidation number of the compound H₂S is 0.
the sum of the oxidation numbers of the individual elements should add up to the oxidation number of the compound. 

(oxidation number of H x 2 H ions) + oxidation number of S = 0
since we know the oxidation number of H, lets name the oxidation number of S = x
(+1 * 2 )+ (x) = 0
2 + x = 0
x = -2
oxidation number of S is -2
You might be interested in
Sodium chloride is composed of molecules that are stable when dry. In water, the atoms of the molecules separate from each other
astra-53 [7]

The molecules of Sodium chloride holds a chemical bond to become stable when dry is an ionic bond.

<h3>What are chemical bonds?</h3>

The chemical bonds are those which holds the atoms of molecules together and creates a temporary connection between them.

The three major types of chemical bonds are:

  • Ionic bonds
  • Covalent bonds
  • Metallic bonds

<h3>What are ionic bonds?</h3>

The ionic bonds generally occurs in between a metal and a nonmetal ions.

The atoms share electrons in between them to become stable, forms ions. Due to electric attraction between these ions forms a bond between them. That bond is called as Ionic bond.

<h3>The type of chemical bond in Sodium chloride:</h3>

Sodium chloride - NaCl

Where Na(sodium) forms Na⁺ ion(metal) by sharing electrons with the chlorine atom and Cl(chlorine) forms Cl⁻ ion(non-metal).

So, due to the attraction between the anion and the cation, a bond is established between them. So, it is called Ionic bond.

Therefore, the chemical bond in Sodium chloride is an Ionic bond.

Learn more about chemical bonds here:

brainly.com/question/704297

#SPJ4

3 0
1 year ago
What can be used to heat a large amount of liquid
Marizza181 [45]
Can be used to heat a large amount of liquid the heat from the sun (solar panels)  or nuclear power or , in the volcanic areas, the natural heat can be used.
4 0
3 years ago
What is the theoretical yield of methanol (ch3oh) when 12.0 grams of h2 is mixed with 74.5 grams of co? co 2h2 ch3oh
sasho [114]
We are given with the reaction that produces methanol from the reaction of hydrogen gas and carbon monoxide. This is expressed in the balanced equation: 2H2+CO=CH3OH. We need to identify the limiting reactant. Convert each mass to moles and divide each with their corresponding stoich. coeff. For H2, this is equal to 3 and for CO, this is equal to 2.66. Hence CO is the limiting reactant. From this, the amount of methanol produced is 85.14 grams. 
4 0
3 years ago
Read 2 more answers
Assuming complete distribution, what is the molarity of 10 milligrams of lisinopril in 100 liters?
SVEN [57.7K]

Answer:

2.47x10^{-7}   M

Explanation:

Lisoprisil's molecular mass is 405.488g/mol, we'll use this fact to calculate molarity, which units are mol/L, and we proceed to the calculus:

  • First, we'll unify unities, the 10 milligrams of lisinopril we'll transform into grams.

10mg*\frac{1g}{1000mg}=0.01g

  • Now that we have the same unities we'll calculate molarity using the molecular mass, the grams of lisinopril and the liters in which these grams are, let's consider that our final unities have to be mol/L.

\frac{1mol}{405.488g}*\frac{0.01g}{100L}=2.47x10^{-7}   M

I hope you find this information useful and interesting! Good luck!

3 0
2 years ago
What is the concentration of a solution of HCl in which a 10.0 mL sample of acid required 50.0 mL of 0.150 M NaOH for neutraliza
puteri [66]

Answer:

The answer is 0.75M HCl

Explanation:

To calculate the concentration of 10 ml of HCl that would be required to neutralize 50.0 mL of 0.150 M NaOH, we use the formula:

To calculate the concentration of 10 ml of HCl that would be required to neutralize 50.0 mL of 0.150 M NaOH, we use the formula:

C1V1 = C2V2

C1 = concentration of acid

C2 = concentration of base

V1 = volume of acid

V2 = volume of base

From the information supplied in the question:

concentration of acid (HCl) is the unknown

volume of acid (HCl) = 10ml

concentration of base (NaOH) = 0.15M

volume of base (NaOH) = 50ml

C1 x 10ml = 0.15M x 50ml

C1 x 10 = 7.5

divide both side by 10

C1 = 0.75M

concentration of acid (HCl) is 0.75M

5 0
3 years ago
Other questions:
  • When atoms are bonded together are they stable or unstable?
    15·1 answer
  • I need help asaaaaap
    10·1 answer
  • What is the most disorganized state of matter?
    11·1 answer
  • Experiments<br> 11. What 2 factors increase the validity of a scientific experiment?
    13·1 answer
  • Peyote has effects similar to those of __________, but with different types of hallucinations.
    7·1 answer
  • When the name of a molecule ends in -ose, the molecule is a
    7·2 answers
  • Q)A certain mass of gas occupies a volume 2.5 L at 90atm. What pressure would the gas exert if it were placed in a 10 L containe
    6·1 answer
  • If the universe is expanding but the expansion is slowing down, what will the eventual
    13·1 answer
  • tetrachloromethane and water can be seperated using a seperating funnel . what can be reduced from this statement
    5·1 answer
  • Iron(111)Carbonate +cesium &gt; cesium carbonate +iron balced
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!