3600 years.
Since 65% of the carbon-14 is remaining, we need to get the logarithm to base 2 of 0.65 to determine how many half lives have expired. So: log(0.65)/log(2) = -0.187086643/0.301029996 = -0.621488377
So we know that 0.621488377 half-lives has gone by to the bone sample. Now we just need to multiply by the half-life of carbon-14 which is 5730 years. So: 0.621488377 * 5730 = 3561.128399 years. Rounding to the nearest 100 years gives us 3600 years.
Answer:
2 HCl + CaCO3 = CaCl2 + H2O + CO2
Explanation:
On the right side we have 2xCl, to get the same amount we will multiply HCl on the left side by 2.
This will give us 2xH on the left side; we also have 2xH on the right side ( in H2O).
On both sides we have 1x Ca; 1x C.
On the left side we have 3XO (in CaCO3), on the right side we have 1O in H20 and 2xO in CO2, so 3x O on the right side as well.
The reaction is balanced.
Answer: When you put a hot object in contact with a cold one it heat will flow from the warmer to the cooler. and as a result the warmer one will be usually cool down and the cooler one will usually warm up. Eventually, they will reach the same temperature and heat flow will stop.
Explanation: Hope this helps
<span>Nitrogen trifluoride - NF3.
1 mol NF3 contains 1 mol atoms of Nitrogen
2.49 mol NF3 contains 2.49 mol atoms of Nitrogen
1 mol ---- 6.02 *10²³ atoms
2.49 mol ----- 2.49*6.02*10²³ = 15.0*10²³ atoms of N</span>
moles of excess reactant remaining: 0.67 mol CS2
moles of each product formed: 0.33 mol CO2 and 0.67 mol SO2
your coefficients in the chemical equation reveal the molar ratio of the reactants that must be present to give a complete reaction of both reactants. in this case each mole of CS2 requires 3 moles of O2 to form the products given. if you start with equimolar amounts of both reactants then the O2 must be in insufficient supply to completely react with all of the CS2. if only 1 mole of O2 is present, it will be consumed by one third that amount of CS2. all O2 will react. 0.67 mole of CS2 will remain. the CO2 comes from the carbon in CS2, so 0.33 mole of CO2 will be produced. since 2 moles of SO2 are produced for each mole of CO2 produced, then the amount of SO2 produced will be 0.67 mol.
