Y = f(3f - 4g + 3) +7g(3f - 4g + 3)
= 3f^2 - 4fg + 3f + 21fg - 28g^2 + 21g
= 3f^2 + 3f + 17fg + 21g - 28g^2
Answer:
1. 9 < s < 17
2. 5 < MN < 19
3. AD > BD
Step-by-step explanation:
1. The triangle inequality tells you the sum of any two sides of a triangle must exceed the length of the other side. (Some versions say, "must be not less than ..." rather than "must exceed.") In practice, this means two things:
- the sum of the shortest two sides is greater than the length of the longest side
- the length of any side lies between the sum and the difference of the other two sides
Here, we can use the latter fact to write the desired inequality. The difference of the given sides is 13 -4 = 9; their sum is 13 +4 = 17. The third side must lie between 9 and 17. If that side length is designated "s", then ...
9 < s < 17
(If you don't mind a "triangle" that looks like a line segment, you can use ≤ instead of <.)
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2. Same as (1) using different numbers.
12 -7 < MN < 12 +7
5 < MN < 19
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3. Side CD is congruent to itself, and side CA is shown congruent to side CB. This means the requirements of the Hinge Theorem are met. That theorem tells you the longer side is opposite the greater angle:
AD > BD
First you need to make both bases the same:
Lets remove the ^p and ^4
To make the base of 42 equal to 41, you would have 41^x = 41
X - ln(42) / ln(41) = 1.00648904
Now you have 41^1.00648904(p) = 41^4
Now the bases are equal so we need to set the exponents to equal:
1.00648904(p) = 4
Divide both sides by 1.00648904 to solve for P
P = 4 / 1.00648904
P = 3.97421114
Answer:
12x - 6 ≤ - 18
Step-by-step explanation:
We will call "a number" x so
Twelve times a number would be:
12x
Then minus 6
12x - 6
Now we add the less than or equal to sign.
12x - 6 ≤
This is equal to negative eighteen, so:
12x - 6 ≤ - 18
As a bonus we can also solve for x.
12x - 6 = - 18 Add 6 to each side.
12x - 6 + 6 = -18 + 6
12x = -18 + 6
12x = -12 Divide each side by 12
12x/12 = -12/12
x = -12/12
x = -1
So we can say when x ≤ -1 Then 12x - 6 ≤ -18
