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2 years ago

A rectangular patio has a length of 558 and a width of 112 . What is the area?

Mathematics

2 answers:

bulgar [2K]2 years ago

8 0

Answer:

Solution given:

length [L]=558

width[W]=112

Now

area of rectangular patio :LW=558*112

=<u>62496</u>

torisob [31]2 years ago

3 0

Answer:

Area of a rectangle is given by product of length and width. Hence width is area divided by length.

$\sf{ \boxed{ as \ area \ is \: 5 \frac{3}{8} = \frac{4}{38}}}$

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Im bad at composite figures || please hurry

goldfiish [28.3K]

The figure is the combination of trapezoid and square. Then the area of the figure will be 39 square meters.

The complete question is attached below.

<h3>What is Geometry?</h3>

It deals with the size of geometry, region, and density of the different forms both 2D and 3D.

The figure is the combination of trapezoid and square.

Then the area of the geometry will be

Area = Area of trapezoid + Area of square

Area = 1/2 x (3 + 9) x 5 + 3 x 3

Area = 30 + 9

Area = 39 square meters

More about the geometry link is given below.

brainly.com/question/7558603

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1 year ago

Please help! ill give brainliest

anastassius [24]

Answer:

y=-6

Step-by-step explanation:

1. plug in the values, it will be y=4/3(-6) + 2

2. simplify

y=-24/3 + 2

y=-8+2

y=-6

I hope this helped, and if it did, please mark this as brainliest! thanks

4 0

2 years ago

Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE

EleoNora [17]

Answer:

0, 10

Step-by-step explanation:

The given function is:

$g(y) = \frac{y-5}{y^2-3y+15}$

According to the quotient rule:

$d(\frac{f(y)}{h(y)}) = \frac{f(y)*h'(y)-h(y)*f'(y)}{h^2(y)}$

Applying the quotient rule:

$g(y) = \frac{y-5}{y^2-3y+15}\\g'(y)=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}$

The values for which g'(y) are zero are the critical points:

$g'(y)=0=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}\\(y-5)*(2y-3)-(y^2-3y+15)=0\\2y^2-3y-10y+15-y^2+3y-15\\y^2-10y=0\\y=\frac{10\pm \sqrt 100}{2}\\y_1=\frac{10-10}{2}= 0\\y_2=\frac{10+10}{2}=10$

The critical values are y = 0 and y = 10.

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3 years ago

5. Determine the 2d shape that would be created if the 3d shape were sliced as shown.

geniusboy [140]

Sorry love i’m so sure but harry might know....?

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2 years ago

Find the length of AB.<br> АE:14<br> AD:12<br> AB:<br> BC:18

Afina-wow [57]

Answer:

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2 years ago