Answer:
length of side of square = (4x - 5) inches
Step-by-step explanation:
We are given;
Area of square = 16x² – 40x + 25
Let's find the roots of this quadratic equation [-b ± √(b² - 4ac)]/2a
Thus;
x = [-(-40) ± √((-40)² - 4(16 × 25)]/(2×16)
x = [40 ± √(1600 - 1600)]/32
x = (40 ± 0)/32
x = 40/32
x = 5/4
Thus, the factors of the polynomial are;
(4x - 5)²
So,
Area = 16x² – 40x + 25 = (4x - 5)²
Since, the right hand side is (4x - 5)² and area of square is (length of side)², thus we can say that length of side of square is (4x - 5) inches
(x^m) times (x^n)=x^(m+n)
(1/8)^5 times (1/8)^3=(1/8)^(5+3)=(1/8)^8=1/(8^8)
Answer:
2/3( x^2 + 5 ) = 14 or 2/3x^2 - 32/3
Step-by-step explanation:
Part 1:
Two-thirds ( 2/3 )
of the ( (---) )
sum ( + )
of a number squared ( x^2 ) and 5 ( + 5 )
is fourteen ( = 14 )
Part 2 (Not super confident about):
2/3( x^2 + 5 ) = 14
2/3x^2 + 10/3 = 14
2/3x^2 - 32/3
Hopefully this helps!
Brainliest please?
A is correct.
-8, -4, 0, 2
-|-4| becomes -(4) which becomes -4.
Answer:
865
Step-by-step explanation: The set of possibilities are:
Subcommittee is of 4 people according to:
4 teachers 0 other member total possibilities 1
3 teachers 1 teachers C₄,₃ = 4 and other member 6 6*4 = 24
2 teachers 2 C₄,₂ = 4!/2! = 12 2 (om) and C₆,₂ = 6!/4! = 30
30*12 = 360
1 teacher 3 (om) 4 and C₆,₃ = 6!/3! = 120
120*4 = 480
Total ways of committee 1 + 24 + 360 + 480 = 865
