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Katen [24]
2 years ago
8

If f(x) and g(x) are polynomial functions, what is the domain of f(x) + g(x) ?

Mathematics
1 answer:
IRINA_888 [86]2 years ago
7 0

Answer:

all real numbers or (-\infty, \infty)

Step-by-step explanation:

since both f(x) and g(x) are polynomials, neither of them have restrictions on their domains. Since they can be defined for all real numbers. It's not like the square root which has a domain of (0, infinity), or log x which is defined only from (0, infinity). So adding these two polynomials would result in a domain of all real numbers.

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A, B & C form a triangle where Z BAC = 90°.
zhannawk [14.2K]

Answer:

BC ≈ 8.6

Step-by-step explanation:

Using Pythagoras' identity in the right triangle , that is

BC² = AB² + AC² = 7.3² + 4.6² = 53.29 + 21.16 = 74.45 ( square root both sides )

BC = \sqrt{74.45} ≈ 8.6 ( to 1 dec. place )

8 0
2 years ago
Question 3. Simplify the following in four steps.
miss Akunina [59]

Answer:

X ¹/₅

Step-by-step explanation:

X ⁷/₁₀

X ¹/₂

apply the exponent rule:

= X ⁷/₁₀ - ¹/₂

= X ¹/₅

3 0
3 years ago
Read 2 more answers
The value of the definite integral / 212x – sin(x) dx / 122x-sin(x) is
blondinia [14]

Hi there!

\boxed{= 70 + cos(12) - cos(2) \approx 71.26}

\int\limits^{12}_{2} {x-sin(x)} \, dx

We can evaluate using the power rule and trig rules:

\int x^n = \frac{x^{n+1}}{n+1}

\int x = \frac{1}{2}x^{2}

\int -sin(x) = cos(x)

Therefore:

\int\limits^{12}_{2} {x-sin(x)} \, dx = [\frac{1}{2}x^{2}+cos(x)]_{2}^{12}

Evaluate:

(\frac{1}{2}(12^{2})+cos(12)) - (\frac{1}{2}(2^2)+cos(2))\\= (72 + cos(12)) - (2 + cos(2))\\\\= 70 + cos(12) - cos(2) \approx 71.26

3 0
2 years ago
Please I need help!​
SashulF [63]

Answer:

M and P

Step-by-step explanation:

they do not cross each other

5 0
3 years ago
Multiply and divide. product or quotient
Mandarinka [93]
Multiply is product. Divide is quotient
7 0
3 years ago
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