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yaroslaw [1]
3 years ago
5

3/4(-10+2/5) Please help I will mark branliest​

Mathematics
2 answers:
konstantin123 [22]3 years ago
8 0
I think its -36/5 or -7 1/5, or -7.2 but im not entirely sure so
In-s [12.5K]3 years ago
4 0

Answer:

-36/5

Step-by-step explanation:

its 36/5 but the whole thing is negative

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Line CD is constructed by making arcs centered at point A and point B with the same compass width.
Pavel [41]

Answer:

C. AB=CD not necessarily true

Step-by-step explanation:

A.

AD = DB True because the width of the compass was the same and hence the radius was same for both centers A and B

B. AE=EB True

CD makes the perpendicular bisectors if arcs are made with compass of same width

C. AB=CD . There is no property which says that it is necessarily true

D. AC=CB True because the width of the compass was the same and hence the radius was same for both centers A and B

3 0
3 years ago
Mina uses 128 pounds of dog food to feed her 16 dogs. find the unit rate per dog
MAXImum [283]

The unit rate is 8 pounds per dog.

128 / 16 = 8

7 0
3 years ago
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A spinner is divided into 8 equal sections, and each section contains a number from 1 to 8. What is the probability of the spinn
alukav5142 [94]

Answer:

more than likely none

Step-by-step explanation:

because the is no number higher than 8 that can go into 8 evenley

8 0
3 years ago
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What is the value of [(2/3)^0]^-3
o-na [289]

Answer:

1

Step-by-step explanation:

Easy because whenever the exponent is 0 the answer must always be 1 then the exponent on the outside it would still be 1.

5 0
3 years ago
Tan(2 sin^-1 0.4)<br> Find the Exact value
stiv31 [10]

Answer:

tan(2u)=[4sqrt(21)]/[17]

Step-by-step explanation:

Let u=arcsin(0.4)

tan(2u)=sin(2u)/cos(2u)

tan(2u)=[2sin(u)cos(u)]/[cos^2(u)-sin^2(u)]

If u=arcsin(0.4), then sin(u)=0.4

By the Pythagorean Identity, cos^2(u)+sin^2(u)=1, we have cos^2(u)=1-sin^2(u)=1-(0.4)^2=1-0.16=0.84.

This also implies cos(u)=sqrt(0.84) since cosine is positive.

Plug in values:

tan(2u)=[2(0.4)(sqrt(0.84)]/[0.84-0.16]

tan(2u)=[2(0.4)(sqrt(0.84)]/[0.68]

tan(2u)=[(0.4)(sqrt(0.84)]/[0.34]

tan(2u)=[(40)(sqrt(0.84)]/[34]

tan(2u)=[(20)(sqrt(0.84)]/[17]

Note:

0.84=0.04(21)

So the principal square root of 0.04 is 0.2

Sqrt(0.84)=0.2sqrt(21).

tan(2u)=[(20)(0.2)(sqrt(21)]/[17]

tan(2u)=[(20)(2)sqrt(21)]/[170]

tan(2u)=[(2)(2)sqrt(21)]/[17]

tan(2u)=[4sqrt(21)]/[17]

7 0
3 years ago
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