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Tcecarenko [31]
3 years ago
10

Described how the HCS12 MCU uses a vector to find the correct interrupt service routine after an interrupt occurs.

Computers and Technology
1 answer:
Arte-miy333 [17]3 years ago
7 0

Answer:

In the HC12 MCU, the starting address of interrupts is stored in the vector table as a vector. The ISR or interrupt service routine fetches the vector of the interrupt to be executed.

Explanation:

The HC12 or 68HC12 microcontroller was developed by Motorola, its controllers have a clock speed of between 8 to 33MHz.

The MCU stores interrupt events in a vector table where the interrupt service routine fetches enabled interrupt to execute.

When an interrupt is detected, the MCU stores all its registers in a stack to be able to return to the program it was previously running, then it disables the maskability flag register to prevent another maskable interrupt from occurring during the current interrupt execution.

The MCU interrupt service routine fetches the required interrupt from the vector table. After the interrupt is executed, the mask flag is enabled and the MCU retrieves or returns back to the previous program in the stack.

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Subtract (100000)2 from (111)2 using 1s and 2s complement method of subtraction​
GenaCL600 [577]

Answer:

-11001

Explanation:

The following steps are performed in order to perform subtraction of the given binary numbers:

Step 1:

Find 2’s complement of the subtrahend. The subtrahend here is 100000

100000

First take 1's complement of 100000

1's complement is taken by inverting 100000

1's complement of 100000 = 011111

Now takes 2's complement by adding 1 to the result of 1's complement:

011111 + 1 = 100000

2's complement of 100000 = 100000

Step 2:

Add the 2's complement of the subtrahend to the minuend.

The number of bits in the minuend is less than that of subtrahend. Make the number of bits in the minuend equal to that of subtrahend by placing 0s in before minuend. So the minuend 111 becomes:

000111

Now add the 2's complement of 100000 to 000111

   0 0 0 1  1  1

<u>+   1 0 0 0 0 0 </u>

    1 0 0 1  1  1

The result of the addition is :

 1 0 0 1  1  1

Step 3:

Since there is no carry over the next step is to take 2's complement of the sum and place negative sign with the result as the result is negative.

sum =   1 0 0 1  1  1

2's complement of sum:

First take 1's complement of 1 0 0 1  1  1

1's complement is taken by inverting 1 0 0 1  1  1

1's complement of 1 0 0 1  1  1 = 0 1 1 0 0 0

Now takes 2's complement by adding 1 to the result of 1's complement:

0 1 1 0 0 0 + 1 = 0 1 1 0 0 1

Now place the minus sign with the result of 2's complement:

- 0 1 1 0 0 1

Hence the subtraction of two binary numbers (100000)₂ and (111)₂  is

(-011001)₂

This can also be written as:

(-11001)₂

6 0
3 years ago
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