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3 years ago

Is the following relation a function?

Mathematics

1 answer:

abruzzese [7]3 years ago

7 0

Answer:

Yes bc the x is not repeating

Step-by-step explanation: Remember if the domain(x) is repeating like (4,4) (4,3) it is not a function because of the x and don't worrying about the y (range) and if the domain is not repeating like (2,3)(3,8) it is a function bc of the domain (x) hope this help:)

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Add (4x+4)+(5b+3) simplify your Answer. Help

yarga [219]

Answer:

5+4+7

Step-by-step explanation:

I think

5 0

3 years ago

Read 2 more answers

The value of <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B%20-%2025%7D%20" id="TexFormula1" title=" \sqrt{ - 25} " alt=" \

Andreas93 [3]

2.23606797749979
This is the answer

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2 years ago

Please answer question three and four if you can :) Show full working out ty;)

nikklg [1K]

Step-by-step explanation:

Let D be the mid point of side BC, [B(2, - 1), C(5, 2)].

Therefore, by mid-point formula:

$D = ( \frac{2 + 5}{2}, \: \: \frac{ - 1 + 2}{2} ) = ( \frac{7}{2}, \: \: \frac{ 1}{2} ) \\ \therefore D= (3.5, \: \: 0.5) \\ \& \: A=(-1,\:\:4)...(given) \\\\ now \: by \: distance \: formula \\ \\ Length \: of \: segment \: AD \\ = \sqrt{( - 1 - 3.5)^{2} + {(4 - 0.5)}^{2} } \\ = \sqrt{(4.5)^{2} + {(3.5)}^{2} } \\ = \sqrt{20.25 + 12.25 } \\ = \sqrt{32.5} \\ \red{ \boxed{\therefore Length \: of \: segment \: AD = 5.7 \: units}}$

4 (a)

Equation of line AB[A(2, 1), B(-2, - 11)] in two point form is given as:

$\frac{y-y_1}{y_1-y_2} =\frac{x-x_1}{x_1 - x_2} \\\\\therefore \frac{y-1}{1-(-11)} =\frac{x-2}{2 - (-2) } \\\\\therefore \frac{y-1}{1+11} =\frac{x-2}{2 +2} \\\\\therefore \frac{y-1}{12} =\frac{x-2}{4} \\\\\therefore \frac{y-1}{3} =\frac{x-2}{1} \\\\\therefore y-1= 3(x - 2)\\\\\therefore y= 3x - 6+1\\\\\therefore y= 3x - 5\\\\ \huge \purple {\boxed {\therefore 3x - y-5=0}} \\$

is the equation of line AB.

Now we have to check whether C(4, 7) lie on line AB or not.

Let us substitute x = 4 & y = 7 on the Left hand side of equation of line AB and if it gives us 0, then C lies on the line.

$LHS = 3x - y-5\\=3\times 4-7-5\\= 12-12\\=0\\= RHS$

Hence, point C (4, 7) lie on the straight line AB.

4(b)

Like we did in 4(a), first find the equation of line AB and then substitute the coordinates of point C in equation and if they satisfy the equation, then all the three points lie on the straight line.

4 0

4 years ago

10) What is the area of the figure below? Round your answer to the nearest tenth (1 place

snow_lady [41]

Answer:

Step-by-step explanation:

Divide the figure into a rectangle and a triangle.

area of rectangle = 5×10 = 50 square units

area of triangle = 0.5×5×10 = 25 square units

total area = 50+25 = 75 square units

8 0

3 years ago

Use the Midpoint Rule and the given data to estimate the value of the integral I. (Give the answer to two decimal places.)

svlad2 [7]

Answer:

a) integral = 24.72

b) |Error| ≤ 0.4267

Step-by-step explanation:

The integral:

$\int_{0}^{3.2} f(x) dx$

can be approximated with the midpoint rule, as follows:

6.7*(0.8 - 0.0) + 8.9*(1.6 - 0.8) + 6.9*(2.4-1.6) + 8.4*(3.2 - 2.4) = 24.72

(that is, all the intervals are 0.8 units length and f(x) is evaluated in the midpoint of the interval)

b)The error bound for the midpoint rule with n points is:

|Error| ≤ K*(b - a)^3/(24*n^2)

where b and are the limits of integration of the integral and K = max |f''(x)|

Given that -5 ≤ f''(x) ≤ 1, then K = 5. Replacing into the equation:

|Error| ≤ 5*(3.2 - 0)^3/(24*4^2) = 0.4267

5 0

3 years ago