Answer:
First option: cos(θ + φ) = -117/125
Step-by-step explanation:
Recall that cos(θ + φ) = cos(θ)cos(φ) - sin(θ)sin(φ)
If sin(θ) = -3/5 in Quadrant III, then cos(θ) = -4/5.
Since tan(φ) = sin(φ)/cos(φ), then sin(φ) = -7/25 and cos(φ) = 24/25 in Quadrant II.
Therefore:
cos(θ + φ) = cos(θ)cos(φ) - sin(θ)sin(φ)
cos(θ + φ) = (-4/5)(24/25) - (-3/5)(-7/25)
cos(θ + φ) = (-96/125) - (21/125)
cos(θ + φ) = -96/125 - 21/125
cos(θ + φ) = -117/125
Answer:
Please check the explanation.
Step-by-step explanation:
We know that when a consistent system has infinite solutions, then the graphs of the equations are exactly the same. In other words, these equations are called dependent equations.
All points of dependent equations share the same slope and same y-intercept.
For example,
6x-2y = 18
9x-3y=27
represent the dependent equations.
Writing both equations in slope-intercept form
y=mx+c
where m is the slope and c is the y-intercept
Now
6x-2y=18
2y = 6x-18
Divide both sides by 2
y = 3x - 9
Thus, the slope = 3 and y-intercept = b = -9
now
9x-3y=27
3y = 9x-27
Divide both sides by 3
y = 3x - 9
Thus, the slope = 3 and y-intercept = b = -9
Therefore, both equations have the same slope and y-intercept. Their graphs are the same. Hence, they are called dependent equations.
Answer:
A) College Student
Step-by-step explanation:
The formula for the discriminant is b^2-4ac. The formula you wote is in the form of
ax^2+c=0, so first, you need to bring that -2 to the left. When you do that, you get (the original equation would be ax^2+bx+c but you have no bx.)
3x^2-8
So, since there's no b, it would be
b^2-4ac
0^2-4(3)(-8
-12 x -8
96
X+8y=18
-5x+3y=-4
Multiply the first equation by 5
Add the two equations together
5x+40y=90
-5x+3y=-4
43y=86
Y=2
Plug y into one equation to find x
X+16=18
X=2
