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3 years ago

Find the inverse: f(x) = 4 + 4/5 x.

Mathematics

1 answer:

timama [110]3 years ago

7 0

Answer:

f−1(x)=5x4−5

Step-by-step explanation:

To find the inverse, interchange the variables and solve for y.

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For altitudes up to 36,000 feet, the relationship between ground temperature and atmospheric

Anon25 [30]

Answer:

a=16400 feet

Step-by-step explanation:

t = -0.0035 a +g

-17.40 = -0.0035 a+40

-17.40-40=-0.0035a+40-40

-57.40=-0.0035a

a = -57.40/-0.0035

a=16400 feet

7 0

4 years ago

Which set of numbers shows all factors of 18

Alexxx [7]

Answer:

Step-by-step explanation: Factors of 18: The square root of 18 is 4.2426, rounded down to the closest whole number is 4. Testing the integer values 1 through 4 for division into 18 with a 0 remainder we get these factor pairs: (1 and 18), (2 and 9), (3 and 6). The factors of 18 are 1, 2, 3, 6, 9, 18.

hope this helps ^-^

5 0

3 years ago

Express 7 million in scientific notation

Novay_Z [31]

Answer:

Step-by-step explanation:

10^9 x 0.007

5 0

3 years ago

Refer to the random sample of customer order totals with an average of $78.25 and a population standard deviation of $22.50. a.

zysi [14]

Answer:

a) $78.25- 1.64 \frac{22.50}{\sqrt{40}}= 72.416$

$78.25+ 1.64 \frac{22.50}{\sqrt{40}}= 84.084$

b) $78.25- 1.64 \frac{22.50}{\sqrt{75}}= 73.989$

$78.25+ 1.64 \frac{22.50}{\sqrt{75}}= 82.511$

c) For this case when we increase the sample size the margin of error would be lower and then the interval would be narrower

d) $ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

Solving for n we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

And replacing the info we have:

$n=(\frac{1.640(22.50)}{5})^2 =54.46 \approx 55$

Step-by-step explanation:

Part a

For this case we have the following data given

$\bar X = 78.25$ represent the sample mean for the customer order totals

$\sigma =22.50$ represent the population deviation

$n= 40$ represent the sample size selected

The confidence level is 90% or 0.90 and the significance level would be $\alpha=0.1$ and $\alpha/2 = 0.05$ and the critical value from the normal standard distirbution would be given by:

$z_{\alpha/2}=1.64$

And the confidence interval is given by:

$\bar X -z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$78.25- 1.64 \frac{22.50}{\sqrt{40}}= 72.416$

$78.25+ 1.64 \frac{22.50}{\sqrt{40}}= 84.084$

Part b

The sample size is now n = 75, but the same confidence so the new interval would be:

$78.25- 1.64 \frac{22.50}{\sqrt{75}}= 73.989$

$78.25+ 1.64 \frac{22.50}{\sqrt{75}}= 82.511$

Part c

For this case when we increase the sample size the margin of error would be lower and then the interval would be narrower

Part d

The margin of error is given by:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

Solving for n we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

And replacing the info we have:

$n=(\frac{1.640(22.50)}{5})^2 =54.46 \approx 55$

3 0

3 years ago

Is there a trick to find?

tigry1 [53]

Answer:

I don't believe so

Step-by-step explanation:

generally for fractions, you can start by simplifying

to simplify divide the numerator and denominator by a common factor

in this case, there is no common factor, so this either your answer or you can divide 729 by 4096 to get a decimal number (0.118)

4 0

3 years ago

Read 2 more answers